Step-by-step explanation:
−2(4y+1)=−8y−2
4y+1=4y+1
infinite solutions
Answer:
Infinitely many solutions
-2(4y+1)=−8y−2
=> -2(4y)-2(1)= -8y-2
=> -8y-2=-8y-2
=> Infinitely many solutions as x from both sides get cancelled
yes
mark brainliest
i hope this will help :)
whole
The second term is 3
C(n)=-6(-1/3) n-1
The first term of the sequence
C(1) = -6(-1/3)1-1
C(1) = (2)-1
C(1) = 1
The second term of the sequence
C(2) = -6(-1/3)2-1
C(2) = -6(-2/3)-1
C(2) = 4-1
C(2) = 3
=0
