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4 years ago

Which graph shows a function where f(2) = 4??? PLEASE HELP MEEE

Mathematics

1 answer:

taurus [48]4 years ago

3 0

Answer:

A 2,100-square-foot home in Cheyenne, WY , costs $110 per square foot. How much does this home cost? (Do not enter anything but numbers for the answer or it will count it wrong. Follow directions please because I am not coming back to grade if you mess up)

Step-by-step explanation:

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Liam has 3 boxes of baseball cards with 50 cards in each box. He also has 5 boxes with 40 basketball cards in each box. If Liam

horsena [70]

Answer:

400 (Sorry if its wrong.)

Step-by-step explanation:

50×3=150

5×40= 200

150+200= 350

350+50=400

3 0

3 years ago

Read 2 more answers

In the rhombus m<1 = 160 what are m<2 and m<3

Luba_88 [7]

The others are either 160 and 70 or 70 and 70

4 0

4 years ago

The coordinates of the turning point of the parabola whose equation is y = x2 — 6x + 8 are A. (3, 35) C. (-3, 35) B. (-3, —1) D.

quester [9]

Answer:

D. (3. —1)

Step-by-step explanation:

Vertex of a quadratic function:

Suppose we have a quadratic function in the following format:

$f(x) = ax^{2} + bx + c$

It's vertex is the point $(x_{v}, y_{v})$

In which

$x_{v} = -\frac{b}{2a}$

$y_{v} = -\frac{\Delta}{4a}$

Where

$\Delta = b^2-4ac$

If a<0, the vertex is a maximum point, that is, the maximum value happens at $x_{v}$ , and it's value is $y_{v}$ .

Turning point of a quadratic function:

The turning point of a quadratic function is the vertex.

y = x2 — 6x + 8

This means that $a = 1, b = -6, c = 8$

Now, we find the vertex.

$x_{v} = -\frac{b}{2a} = -\frac{-6}{2(1)} = 3$

$\Delta = b^2-4ac = (-6)^2-4(1)(8) = 36 - 32 = 4$

$y_{v} = -\frac{4}{4(-1)} = -1$

(x,y) = (3,-1), and the correct answer is given by option D.

6 0

3 years ago

A couple deposits $21,000 into an account earning 7% annual interest for 20 years. Calculate the future value of the investment

Reil [10]

$~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$21000\\ r=rate\to 7\%\to \frac{7}{100}\dotfill &0.07\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years\dotfill &20 \end{cases}$