Question

Countdown until matching digits Write a program that takes in an integer in the range 11-100 as input. The output is a countdown starting from the integer, and stopping when both output digits are identical. Ex: If the input is the output is 93 92 91 90 89 88 Ex: If the input is 11 the output is 11 Ex: If the input is 9 or any number not between 11 and 100 (inclusive), the output is: Input must be 11-100 For coding simplicity, follow each output number by a space, even the last one. Use a while loop. Compare the digits do not write a large if-else for all possible same-digit numbers (11,22,33...99), as that approach would be cumbersome for larger ranges. 29999.1122120 LAB ACTIVITY 4.13.1: LAB: Countdown until matching digits 7/10 main.c Load default template... 1 include 2 3 int main() 4 int n, i: 5 scanf("%d", &n); if (n < 20 Il n98) { 7 printf("%d",n); } else { i-n: 1e while (1) printf("%d", 1); if (icie - i/10) 13 14 15 16 17 } 18 printf("\n"); 19 return : 20 ) 12 break; Latest submission - 11:16 PM on 02/05/21 Total score: 7/10 Only show failing tests Download this submission 1: Compare output A 3/3 Input Your output 93 92 91 90 89 88 2: Compare Output A Input 11 Your output 11 3: Compare output a 3/3 Input 20 Your output 20 19 18 17 16 15 14 13 12 11 4: Compare output A 0/2 Output differs. See highlights below. Special character legend Input 101 Your output 101 Expected output Input must be 11-100 5. Compare output A 0/1 Output differs. See highlights below. Special character legend Input Your output Expected output Input must be 11-100

Answer 1

Answer:

The program in C is as follows:

#include <stdio.h>

int main(){

   int n;

   scanf("%d", &n);

   if(n<11 || n>100){

       printf("Input must be between 11 - 100");    }

   else{

       while(n%11 != 0){

           printf("%d ", n);

           n--;        }

       printf("%d ", n);    }

   return 0;

}

Explanation:

The existing template can not be used. So, I design the program from scratch.

This declares the number n, as integer

   int n;

This gets input for n

   scanf("%d", &n);

This checks if input is within range (11 - 100, inclusive)

   if(n<11 || n>100){

The following prompt is printed if the number is out of range

       printf("Input must be between 11 - 100");    }

   else{

If input is within range, the countdown is printed

       while(n%11 != 0){ ----This checks if the digits are identical using modulus 11

Print the digit

           printf("%d ", n);

Decrement by 1

           n--;        }

This prints the last expected output

       printf("%d ", n);    }