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cricket20 [7]
3 years ago
15

By limiting the number of times a person can use a type of software before registering as the authorized owner of that software,

software firms are dealing with problems associated with:
Computers and Technology
1 answer:
alexira [117]3 years ago
8 0

Answer:

Software piracy.

Explanation:

A software can be defined as a set of executable instructions (codes) or collection of data that is used typically to instruct a computer on how to perform a specific task and solve a particular problem.

Simply stated, it's a computer program or application that comprises of sets of code for performing specific tasks on the system.

Basically, softwares are categorized into two (2) main categories and these are;

I. Open-source software.

II. Proprietary software.

A proprietary software is also known as a closed-source software and it can be defined as any software application or program that has its source code copyrighted and as such cannot be used, modified or distributed without authorization from the software developer. Thus, it is typically published as a commercial software that may be sold, licensed or leased by the software developer (vendor) to the end users with terms and conditions.

Some examples of proprietary software are Microsoft Windows, macOS, Adobe photoshop etc.

Furthermore, a proprietary software license avail end users the opportunity to install and use the software after agreeing to the terms of its license.

Software piracy can be defined as an act which typically involves the unauthorized use, duplications, or distribution of a software that is legally copyrighted or protected, without an express permission from the software manufacturer (owner).

Generally, software manufacturers (owners) deal with problems associated with software piracy by placing a limit on the number of times or durations that an end user is allowed to use a particular software before registering (subscribing) as the authorized owner of that software.

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Sftp uses which mechanism to provide security for authentication and data transfer?
12345 [234]

Sftp uses SSH mechanism to provide security for authentication and data transfer.

<h3>What are SSH known for?</h3>

SSH or Secure Shell is known to be a kind of a network communication protocol that helps two computers to be able to communicate and also  share their data.

Therefore, one can say that Sftp uses SSH mechanism to provide security for authentication and data transfer.

Learn more about  SSH mechanism from

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#SPJ12

3 0
2 years ago
1. What are the biggest password mistakes that people and companies make? How can you avoid those mistakes?
Ghella [55]

Answer:

1. Keeping a password with user name or password is very easy word.

2. Passwords should be kept strong so that it cannot be haccked. One should use upper case letters along with lower case letters and numeric and special characters to make the password strong.

3. The businesses usually run anti viruses in case of virus attack. In case of haccker attack businesses are temporarily shut down from their routine work and alternate business plan is activated which runs the business activities incognito version.

4. High profile passwords can be leaked as it is on the computer system which can be accessed from around the world.  

Explanation:

The businesses should use DRP system in order to avoid complete shut down of business operations in case of a cyber attack. The passwords should be kept strong enough so that no one can crack the password and all employees should not be given complete access to business operations and planning activities. Employees access should be restricted to their job role.

5 0
3 years ago
A software program that allows you to create professional looking multimedia presentations. Question 1 options: Excel 365 Word 3
maks197457 [2]

Powerpoint is a program that allows  us to create professional looking multimedia presentations.

<h3>What is Multimedia presentations?</h3>

A multimedia presentation is a way of communication where we use audio,vedio,arts,drawings and other various ways to present communcations.

<h3>Why Ms-PowerPoint ?</h3>

Ms-PowerPoint consists of some simple and understandable features to make notes through slides create vedio and vedio editing, Coral Draws Audio editing etc.

We can create banners,record vedios,draw and design with the help of tools provided by powerpoint.

Powerpoint also helps to transform boring presentation to an eye catching presentation.

Learn more about PowerPoint here:brainly.com/question/10117380

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2 years ago
The expression that is tested by a switch statement must have a(n) __________ value.
Hitman42 [59]

The answer is relational.

6 0
4 years ago
Implement a C program to solve the 15-puzzle problem using the A* search algorithm.
fomenos

Answer:

#include<stdio.h>

#include<conio.h>

int m=0,n=4;

int cal(int temp[10][10],int t[10][10])

{

               int i,j,m=0;

               for(i=0;i < n;i++)

                               for(j=0;j < n;j++)

                               {

                                               if(temp[i][j]!=t[i][j])

                                               m++;

                               }

               return m;

}

int check(int a[10][10],int t[10][10])

{

               int i,j,f=1;

               for(i=0;i < n;i++)

                               for(j=0;j < n;j++)

                                               if(a[i][j]!=t[i][j])

                                                               f=0;

               return f;

}

void main()

{

               int p,i,j,n=4,a[10][10],t[10][10],temp[10][10],r[10][10];

               int m=0,x=0,y=0,d=1000,dmin=0,l=0;

               clrscr();

               printf("\nEnter the matrix to be solved,space with zero :\n");

               for(i=0;i < n;i++)

                               for(j=0;j < n;j++)

                                               scanf("%d",&a[i][j]);

               printf("\nEnter the target matrix,space with zero :\n");

               for(i=0;i < n;i++)

                               for(j=0;j < n;j++)

                                               scanf("%d",&t[i][j]);

               printf("\nEntered Matrix is :\n");

               for(i=0;i < n;i++)

               {

                               for(j=0;j < n;j++)

                                               printf("%d\t",a[i][j]);

                               printf("\n");

               }

               printf("\nTarget Matrix is :\n");

               for(i=0;i < n;i++)

               {

                               for(j=0;j < n;j++)

                                               printf("%d\t",t[i][j]);

                               printf("\n");

               }

               while(!(check(a,t)))

               {

                               l++;

                               d=1000;

                               for(i=0;i < n;i++)

                                               for(j=0;j < n;j++)

                                               {

                                                               if(a[i][j]==0)

                                                               {

                                                                               x=i;

                                                                               y=j;

                                                               }

                                               }

                               //To move upwards

                               for(i=0;i < n;i++)

                                               for(j=0;j < n;j++)

                                                               temp[i][j]=a[i][j];

                               if(x!=0)

                               {

                                               p=temp[x][y];

                                               temp[x][y]=temp[x-1][y];

                                               temp[x-1][y]=p;

                               }

                               m=cal(temp,t);

                               dmin=l+m;

                               if(dmin < d)

                               {

                                               d=dmin;

                                               for(i=0;i < n;i++)

                                                               for(j=0;j < n;j++)

                                                                               r[i][j]=temp[i][j];

                               }

                               //To move downwards

                               for(i=0;i < n;i++)

                                               for(j=0;j < n;j++)

                                                               temp[i][j]=a[i][j];

                               if(x!=n-1)

                               {

                                               p=temp[x][y];

                                               temp[x][y]=temp[x+1][y];

                                               temp[x+1][y]=p;

                               }

                               m=cal(temp,t);

                               dmin=l+m;

                               if(dmin < d)

                               {

                                               d=dmin;

                                               for(i=0;i < n;i++)

                                                               for(j=0;j < n;j++)

                                                                               r[i][j]=temp[i][j];

                               }

                               //To move right side

                               for(i=0;i < n;i++)

                                               for(j=0;j < n;j++)

                                                               temp[i][j]=a[i][j];

                               if(y!=n-1)

                               {

                                               p=temp[x][y];

                                               temp[x][y]=temp[x][y+1];

                                               temp[x][y+1]=p;

                               }

                               m=cal(temp,t);

                               dmin=l+m;

                               if(dmin < d)

                               {

                                               d=dmin;

                                               for(i=0;i < n;i++)

                                                               for(j=0;j < n;j++)

                                                                               r[i][j]=temp[i][j];

                               }

                               //To move left

                               for(i=0;i < n;i++)

                                               for(j=0;j < n;j++)

                                                               temp[i][j]=a[i][j];

                               if(y!=0)

                               {

                                               p=temp[x][y];

                                               temp[x][y]=temp[x][y-1];

                                               temp[x][y-1]=p;

                               }

                               m=cal(temp,t);

                               dmin=l+m;

                               if(dmin < d)

                               {

                                               d=dmin;

                                               for(i=0;i < n;i++)

                                                               for(j=0;j < n;j++)

                                                                               r[i][j]=temp[i][j];

                               }

                               printf("\nCalculated Intermediate Matrix Value :\n");

                               for(i=0;i < n;i++)

                               {

                                               for(j=0;j < n;j++)

                                               printf("%d\t",r[i][j]);

                                               printf("\n");

                               }

                               for(i=0;i < n;i++)

                                               for(j=0;j < n;j++)

                                               {

                                               a[i][j]=r[i][j];

                                               temp[i][j]=0;

                                               }

                               printf("Minimum cost : %d\n",d);

               }

               getch();

}

Explanation:

7 0
3 years ago
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