Answer:
19
Step-by-step explanation:
the side is same as 57
what times 3 is 57?
57/3 is 19
AB is 19
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Answer:
(-1, 19) and (3, -81)
Step-by-step explanation:
f(x) = 2x³ − 6x² − 27x
f'(x) = 6x² − 12x − 27
-9 = 6x² − 12x − 27
0 = 6x² − 12x − 18
0 = x² − 2x − 3
0 = (x + 1) (x − 3)
x = -1 or 3
f(-1) = 19
f(3) = -81
The points are (-1, 19) and (3, -81).
Hello:
<span>Use De Moivre’s Theorem :
</span>(3(cos27 +isin27)^5 = 3^5( cos(27 × 5) +isin(27 × 5))
= 3^5 ( cos(135)+i sin(135))
= 3^5(-√2/2+i √2/2)
because : cos(135) = -√2/2 and sin(135) = √2/2
(3(cos27 +isin27)^5 = (- 3^5√2/2)+ i ( 3^5√2/2) ...(form : a+ib when
a= (- 3^5√2/2) and b = ( 3^5√2/2)
Answer:
perpendicular
Step-by-step explanation:
because of the opposite signs
Option E:
The value of m that makes the inequality true is 5.
Solution:
Given inequality is 3m + 10 < 30.
Let us first simplify the expression.
3m + 10 < 30
Subtract 10 from both side of the equation.
3m < 20 – – – – (1)
<u>To find the value of m that makes the inequality true:</u>
Option A: 20
Substitute m = 20 in (1),
⇒ 3(20) < 20
⇒ 60 < 20
It is not true because 60 is greater than 20.
Option B: 30
Substitute m = 30 in (1),
⇒ 3(30) < 20
⇒ 90 < 20
It is not true because 90 is greater than 20.
Option C: 8
Substitute m = 8 in (1),
⇒ 3(8) < 20
⇒ 24 < 20
It is not true because 24 is greater than 20.
Option D: 10
Substitute m = 10 in (1),
⇒ 3(30) < 20
⇒ 90 < 20
It is not true because 90 is greater than 20.
Option E: 5
Substitute m = 5 in (1),
⇒ 3(5) < 20
⇒ 15 < 20
It is true because 15 is less than 20.
Hence the value of m that makes the inequality true is 5.
Option E is the correct answer.