Simplify 6/sqr3+2 NEED HELP PLZ!!

Mathematics

2 answers:

telo118 [61]3 years ago

8 0

Answer:

-6(√3 - 2)

Step-by-step explanation:

Which did you mean?

6/[sqr(3) + 2]

6/(sqr(3)+2)

or what? Ambiguous unless you use parentheses.

If you meant

6/[sqr(3) + 2]

then rationalize the denominator by multiplying numerator and denominator of the given expression by (√3 - 2):

6(√3 - 2) 6(√3 - 2)

-------------------------- = ----------------- = -6(√3 - 2)

[sqr(3) + 2](√3 - 2) 3 - 4

mote1985 [20]3 years ago

5 0

Answer:

1.61

Step-by-step explanation:

6/((sqrt3)+2) in a calculator

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find three consecutive odd integers such that 3 times the sum of all three is 24 more than the product if the first and second i

Delicious77 [7]

3 consecutive odd integers : x, x + 2, x + 4

3(x + x + 2 + x + 4) = x(x + 2) + 24
3(3x + 6) = x^2 + 2x + 24
9x + 18 = x^2 + 2x + 24
x^2 - 7x + 6 = 0
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x = 1

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x = 6 (this will not work...it is even)

ur 3 consecutive odd integers :
x = 1
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Mars2501 [29]

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Solution:

(a)

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