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3 years ago

Let f (x) = 2x^2 – 7and g(x) = 3x + 1. Find f (g (-2)). f(g(-2)) =

Mathematics

1 answer:

Anettt [7]3 years ago

5 0

Step-by-step explanation:

g(-2)=3(-2) +1= -6 + 1= -5

f(g(-2))=f(-5)= 2(-5)^2 -7

=2(25) -7

=50-7

=43

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eimsori [14]

Answer:

Step-by-step explanation:

because it's A.B

C.D.

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3 years ago

Sierra applies a coat of epoxy paint to the four sides and floor of a rectangular swimming pool. The pool is 4 feet deep, 18 fee

Brilliant_brown [7]

Answer:

4 gallons of paint

Step-by-step explanation:

We solve using the formula for surface area of rectangular prism.

A=2(wl+hl+hw)

Where:

w = Width

h = Height

l = Length

The pool is 4 feet deep, 18 feet long, and 12 feet wide.

Hence,

=2 × (12 × 18 + 4 × 18 + 4 ×12)

=672 square feet

One gallon of paint covers 155 square feet.

Hence,

155 square feet = 1 gallon of paint

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Cross Multiply

155 square feet × x = 672 square feet × 1 gallon of paint

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Therefore, based on the calculation above, approximately to the nearest whole number, Sierra uses 4 gallons of paint

4 0

3 years ago

Please help logarithms!

nlexa [21]

Given:

$\log_34\approx 1.262$

$\log_37\approx 1.771$

To find:

The value of $\log_3\left(\dfrac{4}{49}\right)$ .

Solution:

We have,

$\log_34\approx 1.262$

$\log_37\approx 1.771$

Using properties of log, we get

$\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349$ $\left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]$

$\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2$

$\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37$ $[\log x^n=n\log x]$

Substitute $\log_34\approx 1.262$ and $\log_37\approx 1.771$ .

$\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)$

$\log_3\left(\dfrac{4}{49}\right)=1.262-3.542$

$\log_3\left(\dfrac{4}{49}\right)=-2.28$

Therefore, the value of $\log_3\left(\dfrac{4}{49}\right)$ is $-2.28$ .

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3 years ago

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Tatiana [17]

Answer:

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Step-by-step explanation:

8h=240

240÷8=30

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3 years ago

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wel

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Step-by-step explanation:

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2 years ago