All categories

3 years ago

Solve, need an explanation as well. Please

Mathematics

1 answer:

Aliun [14]3 years ago

7 0

Step-by-step explanation:

.05N + .10D = 1.65

.05 is the value of the nickel and .10 is the value of the dime.

N + D = 21 because you have some combination of them that total 21

solve for N: N = 21- D

substitute into the first equation

0.5 (21-D) + .10D = 1.65

1.05 - .05D + .10D = 1.65

.05D = .6

D = 12 you have 12 dimes

21-12 = 9 nickels

You might be interested in

Help please I need this done

julia-pushkina [17]

Step-by-step explanation:

the answer is in the above image

7 0

3 years ago

Read 2 more answers

8 - 26r = 892. Solve for r.

marishachu [46]

R = -34

hope this helps!!

8 0

3 years ago

Read 2 more answers

There are 8 roses in a vase of 13 flowers. The rest are daisies.

Blizzard [7]

Answer:

5:13
8:5

Step-by-step explanation:

For first part:

Roses = 8
Daises = All flowers - Roses
Daises = 13 - 8
Daises = 5
Daises:All Flowers = 5:13

For second part:

Roses:Daises = 8:5

I hope this helps!

7 0

3 years ago

Read 2 more answers

Please help ill mark brainliest

lisabon 2012 [21]

Answer:

x=28

Step-by-step explanation:

3 0

3 years ago

What is the sum of the series? 4 ∑k=1 (2k^2−4)

larisa86 [58]

The sum of the series $\sum_{k=1}^{4}\left(2 k^{2}-4\right)$ is 44.

Step-by-step explanation:

The given series is $\sum_{k=1}^{4}\left(2 k^{2}-4\right)=44$

To find the sum of the series, we need to substitute the values for k in the series.

$\sum_{k=1}^{4}\left(2 k^{2}-4\right)=\left[2(1)^{2}-4\right]+\left[2(2)^{2}-4\right]+\left[2(3)^{2}-4\right]+\left[2(4)^{2}-4\right]$

Now, simplifying the square terms, we get,

$[2(1)-4]+[2(4)-4]+[2(9)-4]+[2(16)-4]$

Multiplying the terms,

$[2-4]+[8-4]+[18-4]+[32-4]$

Subtracting the values within the bracket term, we get,

$-2+4+14+28$

Now, adding all the terms, we get the sum of the series,

$\sum_{k=1}^{4}\left(2 k^{2}-4\right)=44$

Thus, the sum of the series is $\sum_{k=1}^{4}\left(2 k^{2}-4\right)=44$

8 0

3 years ago