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rewona [7]
3 years ago
10

There are 8 roses in a vase of 13 flowers. The rest are daisies.

Mathematics
2 answers:
Blizzard [7]3 years ago
7 0

Answer:

  1. 5:13
  2. 8:5

Step-by-step explanation:

For first part:

  1. Roses = 8
  2. Daises = All flowers - Roses
  3. Daises = 13 - 8
  4. Daises = 5
  5. Daises:All Flowers = 5:13

For second part:

  1. Roses:Daises = 8:5

I hope this helps!

sveta [45]3 years ago
3 0

Answer:

5:13

8:5

Step-by-step explanation:

8 roses out of 13 flowers in the vase, the rest of are daisies. So find how much daisies there are first, 13 - 8 = 5, there are 5 daisies, that means the ratio is 5/13 which is also 5:13

The ratio of roses to daisies is 8/5, which is also 8:5

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3 years ago
A rectangular garden must have a perimeter of 150 feet and an area of at least 1200 square feet. Describe the possible lengths o
kipiarov [429]

Answer: 51.86 and 23.14

Step-by-step explanation:

The rectangular garden must have a perimeter of 150 feet

Perimeter of rectangular garden =

2l + 2w=150 -----------1

The rectangular garden must have a perimeter of 150 feet and an area of at least 1200 square feet.

Area of rectangular garden =

l×w= 1200 feet^2 -----------2

From equation 2, l=1200/w

Put l=1200/w in equation 1

2× 1200/w + 2w = 150

(2400/w) +2w = 150

(2400+2w^2)/w =150

2400+2w^2= 150w

2w^2- 150w+2400=0

Using the general formula

w = [-b+-√(b^2-4ac)]/2a

a = 2, b =-150, c=2400

w =[--150+/-√(-150^2-4×2×2400)]/2×2

=[150+/-√(22500-19200)]/4

=[150+/-√3300)]/4

=(150+57.45)/4 or (150-57.45)/4

w= 207.45/4 or 92.55/4

w= 51.86 or w= 23.14

l = 1200/51.86 or l= 1200/23.14

l = 23.14. or l= 51.86

For an area of at least 1200ft^2

The dimensions are 51.86 and 23.14

4 0
4 years ago
ΔABC has three sides with these lengths: AB = 9, BC = 40, and CA = 41. What is the value of cos C?
kotykmax [81]

Answer:

cos(C) =\frac{40}{41}\\\\cos(C)=0.976

Step-by-step explanation:

To find the cos (C) we must use the cosine theorem.

The cosine theorem says that:

c^2 = a^2 +b^2 -2abcos(C)

In this case:

c=AB = 9

b=CA = 41

a=BC = 40

So

9^2 = 40^2 +41^2 -2(40)*(41)cos(C)

9^2- 40^2- 41^2 =-2(40)*(41)cos(C)

cos(C) = -\frac{9^2- 40^2- 41^2}{2(40)*(41)}

cos(C) =\frac{40}{41}\\\\cos(C)=0.976

7 0
3 years ago
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