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anzhelika [568]
4 years ago
7

Fraction - Multiplication : (a) 2/9 x 1/13 (b) 12/5 x 35/21

Mathematics
2 answers:
anastassius [24]4 years ago
7 0

Answer:

(a) \frac{2}{117}

(b)4

Step-by-step explanation:

(a) \frac{2}{9}  \times  \frac{1}{13}  \\  =  \frac{2}{117}

(b) \frac{12}{5}  \times  \frac{35}{21}  \\  =  \frac{84}{21}  \\  =  \frac{28}{7}  \\  = 4

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em>

<em>brainliest</em><em> </em><em>appreciated</em>

<em>good</em><em> </em><em>luck</em><em>!</em><em> </em><em>have</em><em> </em><em>a</em><em> </em><em>nice</em><em> </em><em>day</em><em>!</em>

Elena L [17]4 years ago
5 0

<em>answer \\ a.  \frac{2}{117} \\ b.  4 \\ solution \\ a. \:  \frac{2}{9}  \times  \frac{1}{13}  \\  =  \frac{2 \times 1}{9 \times 13}  \\  =  \frac{2}{117}  \\ b. \:  \frac{12}{5}  \times  \frac{35}{21}  \\  = divide \: 35 \: by \: 5 \: it \: becomes \\  =  12 \times  \frac{7}{21}  \\ divide \: 21 \: by \: 7 \: it \: becomes \\  = 12 \times  \frac{1}{3}  \\ divide \: 12 \: by \: 3 \: it \: becomes \\  = 4 \times 1 \\  = 4 \\ hope \: it \: helps \\ good \: luck \: on \: your \: assignment</em>

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Yuri [45]

Answer:

a) Null and alternative hypothesis

H_0: \mu=1503\\\\H_a:\mu< 1503

b)  Point estimate d = -$78

c) Test statistic t = -2.438

P-value = 0.0113

Reject H0. We can conclude that the population mean automobile premium in Pennsylvania is lower than the national mean.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that automobile insurance in Pennsylvania is significantly cheaper than the national average.

Then, the null and alternative hypothesis are:

H_0: \mu=1503\\\\H_a:\mu< 1503

The significance level is 0.05.

The sample has a size n=25.

The sample mean is M=1425.

A point estimate of the difference between the mean annual premium in Pennsylvania and the national mean can be calculated with the sample mean:

d=M-\mu=1425-1503=-78

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=160.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{160}{\sqrt{25}}=32

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{1425-1503}{32}=\dfrac{-78}{32}=-2.438

The degrees of freedom for this sample size are:

df=n-1=25-1=24

This test is a left-tailed test, with 24 degrees of freedom and t=-2.438, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=P(t

As the P-value (0.0113) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

At a significance level of 0.05, there is enough evidence to support the claim that automobile insurance in Pennsylvania is significantly cheaper than the national average.

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Answer:

Example:

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