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3 years ago

X2 + 17x + 52 = 0 Find the product sum

Mathematics

1 answer:

satela [25.4K]3 years ago

3 0

Answer:

19x+52=0

19x=-52

Step-by-step explanation:

add the x and move the 52

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Tlaloc pumped up 56 balls. He pumped up 5 dodge balls for every 9 other balls. Complete the table.

Radda [10]

The number of dodgeballs Ttaloc pumped up is 20.

The number of other balls Ttaloc pumped up is 36.

The orginal number of the total ball is 14.

<h3>What are ratios?</h3>

Ratio expresses the relationship between two or more numbers. It shows the frequency of the number of times that one value is contained within other value(s).

The number of dodgeballs Ttaloc pumped up = (5/14) x 56 = 20

The number of other balls Ttaloc pumped up = (9/14) x 56 = 36.

To learn more about ratios, please check: brainly.com/question/25927869

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The area of a rectangle is 1176 square meters. The width of the rectangle is 21 meters. What i the length of the rectangle?

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The length is 56 meters

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A fast-food restaurant was selling 7 boxes of chicken nuggets for $25.90. A competing restaurant was selling 3 boxes of chicken

Svetlanka [38]

Answer:

The competing company is better

7 for 25.90 vs. 7 for 25.83

Step-by-step explanation:

Since it's 3 for 11.07

we need to see how much higher the price will get at 7, so divde 11.07 by 3 then double the price.

3.69 per box for competing company

11.07*2 = 22.14

22.14 + 3.69= 25.83

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3 years ago

- Polynomial Functions -For each function, state the vertex; whether the vertex is a maximum or minimum point; the equation of t

vladimir2022 [97]

EXPLANATION

Given the function f(x) = (x-6)^2 + 1

$\mathrm{The\: vertex\: of\: an\: up-down\: facing\: parabola\: of\: the\: form}\: y=ax^2+bx+c\: \mathrm{is}\: x_v=-\frac{b}{2a}$

Expanding (x-6)^2 + 1 by applying the Perfect Square Formula:

$=x^2-12x+37$ $\mathrm{The\: parabola\: params\: are\colon}$ $a=1,\: b=-12,\: c=37$ $x_v=-\frac{b}{2a}$ $x_v=-\frac{\left(-12\right)}{2\cdot\:1}$ $\mathrm{Simplify}$ $x_v=6$ $y_v=6^2-12\cdot\: 6+37$

Simplify:

$y_v=1$

$\mathrm{Therefore\: the\: parabola\: vertex\: is}$ $\mleft(6,\: 1\mright)$ $\mathrm{If}\: a$ $\mathrm{If}\: a>0,\: \mathrm{then\: the\: vertex\: is\: a\: minimum\: value}$ $a=1$ $\mathrm{Minimum}\mleft(6,\: 1\mright)$ $\mathrm{For\: a\: parabola\: in\: standard\: form}\: y=ax^2+bx+c\: \mathrm{the\: axis\: of\: symmetry\: is\: the\: vertical\: line\: that\: goes\: through\: the\: vertex}\: x=\frac{-b}{2a}$

Expanding (x-6)^2 + 1 by applying the Perfect Square Formula:

$y=x^2-12x+37$ $\mathrm{Axis\: of\: Symmetry\: for}\: y=ax^2+bx+c\: \mathrm{is}\: x=\frac{-b}{2a}$ $a=1,\: b=-12$ $x=\frac{-\left(-12\right)}{2\cdot\:1}$ $\mathrm{Refine}$

Axis of simmetry : x=6

The quadratic function has the same shape than the parent function y=x^2 because there is NOT a coefficient within x.

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