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den301095 [7]
3 years ago
12

Can someone help me solve this?!

Mathematics
2 answers:
Setler79 [48]3 years ago
7 0
To solve an inequality, you solve it just like an equation with an = sign

y-3 ≥ -12
Add 3 to both sides
y ≥ -9

What this means is that y could be any number as long as it’s greater than (bigger) or equal to -9, so y could equal -9, -3, 100, or 0 but could not equal -10,-11, -9.3, or anything less than -9

To graph this, first write in numbers below each of the lines. You want to show -9, a few numbers less than -9 and a few numbers greater than -9. It could look like this:

-11 -10 -9 -8 -7 -6 -5

Then, draw a filled in circle above -9. This shows that y can equal -9. Starting from where you drew the circle, draw an arrow to the right until the graph ends. This shows that y could be any of these numbers greater than -9, too.

I attached an example of a filled in number line for a different problem so you could see what it looks like. I hope this helps!

o-na [289]3 years ago
3 0
y-3-(-12)≥0

y ≥ -9

y + 9.000 ≥ 0

y ≥ -9

I hope this helps!
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Answer:

C

Step-by-step explanation:

0.004, 0.07, 0.6, 0.32

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3 years ago
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The TreeDropp’d Fruit Company wants to sell its apples overseas in attractive pink and yellow gift boxes. To design the boxes, t
SashulF [63]

Answer:

a)For this case the best estimator for the true mean is the sample mean \hat \mu =\bar X because:

E(\bar X)= \frac{\sum_{i=1}^n E(X_i)}{n}

And if we assume that each observation X_1 , X_2,...,X_n follows a normal distribution X_i \sim N(\mu,\sigma) then we have:

E(\bar X)=\frac{1}{n} n\mu =\mu

So then yes the \bar X[/tex[ is a unbiased estimator for the true mean. b) [tex]z_{\alpha/2}=1.96

c) ME= 1.96 \frac{0.4}{\sqrt{50}}=0.1109

Step-by-step explanation:

Previous concepts

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

\bar X=4.1 represent the sample mean  

\mu population mean (variable of interest)  

\sigma=0.4 represent the population standard deviation  

n=50 represent the sample size  

Assuming the X follows a normal distribution  

X \sim N(\mu, \sigma=0.4

The sample mean \bar X is distributed on this way:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

A. What is the point estimate in this scenario? Is it an unbiased estimator?

For this case the best estimator for the true mean is the sample mean \hat \mu =\bar X because:

E(\bar X)= \frac{\sum_{i=1}^n E(X_i)}{n}

And if we assume that each observation X_1 , X_2,...,X_n follows a normal distribution X_i \sim N(\mu,\sigma) then we have:

E(\bar X)=\frac{1}{n} n\mu =\mu

So then yes the \bar X[/tex[ is a unbiased estimator for the true mean. B. What is the critical z-value for a 95% interval?
The next step would be find the value of [tex]\z_{\alpha/2}, \alpha=1-0.95=0.05 and \alpha/2=0.025  

Using the normal standard table, excel or a calculator we see that:  

z_{\alpha/2}=1.96

C. What is the margin of error for a 95% interval in this scenario? Show your work.

The margin of error is given by:

ME= z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

If we replace the values that we have we got:

ME= 1.96 \frac{0.4}{\sqrt{50}}=0.1109

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

Since we have all the values we can replace:

4.1 - 1.96\frac{0.4}{\sqrt{50}}=3.989  

4.1 + 1.96\frac{0.4}{\sqrt{50}}=4.211  

So on this case the 95% confidence interval would be given by (3.989;4.211)  

4 0
3 years ago
Which shape is not always a parallelogram?
Sholpan [36]
B is the answer I think I spend to much
6 0
3 years ago
What is the difference? −15 − (−3)
klasskru [66]
The answer is -12 bc you take away the 3
3 0
1 year ago
Read 2 more answers
Vanessa works 32 hours per week at her job. Her boss offers her a full time job (40 Hours per week) and a 2 dollar per hour rais
FinnZ [79.3K]

Answer:

$35.75 per hour

Step-by-step explanation:

In order to calculate this, we first need to calculate how much she made with her current hourly wage. We do this by multiplying the hours she worked by her current hourly wage plus her raise.

32 hours * (40+2) = $1,344

Now we subtract $200, since this is how much more she is making with her raise, and then we divide that amount by the 32 hours she is working per week.

(1,344 - 200) / 32 = $35.75 per hour

Finally, we can see that Vanessa's hourly wage before the raise was $35.75 per hour

8 0
3 years ago
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