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3 years ago

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The width of a rectangle is 6 feet, and the diagonal length of the rectangle is 12 feet. Which measurement is closest to the len

gth of this rectangle feet
A.10.4 feet
B.13.4 feet
C.4.2 feet
D.2.4 feet

1 answer:

pentagon [3]3 years ago

3 0

Answer:

if you try it on your own then you will get the answers

Step-by-step explanation:

nun

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Two factors of -48 have a difference of 19 the factor with the greater absolute value is positive what is the sum of the factors

MA_775_DIABLO [31]

1). Two factors of -48 => x * y = -48

=> the absolute values of the two numbers may be:

48 and 1

24 and 2

16 and 3

12 and 4

6 and 8

2). Have a differencie of 19 = > x - y = 19

That makes that the numbers be + 16 and - 3

Because (+16) * (-3) = - 48

And +16 - (-3) = +16 + 3 = 19.

3) The sum of the factors is +16 + (-3) = 16 - 3 = 13.

So the answer is the option C. 13.

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3 years ago

Simplify the polynomial (4n2 + 3n - 5) - (2n2 + 3n+ 6)

saul85 [17]

Answer:

2n^2 - 11

steep by steep explanation

=(4n^2 + 3n -5) -(2n^2 + 3n +6)

= 4n^2 +3n -5 - 2n^2 - 3n -6

= 2n^ - 11

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3 years ago

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I really really need this answer PLSSSSSSSSS

ikadub [295]

Answer: x=112

Step-by-step explanation: If you add 35 and 33 you would get 68 and if you subtract 68 from 180 you will get 112. I hope this helps!

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3 years ago

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Please help guys ♡♡♡♡♡♡

Oksanka [162]

Answer:

I'm pretty sure the Y position of the eyes is 70.

If the Variable Y is equal to 70, and the Y variable is where the Y axis value goes. Then the Y position of the eyes is equal to the Y variable which is 70. I think that makes sense, but feel free to comment if it does not so that I can help you figure it out.

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3 years ago

A programmer plans to develop a new software system. In planning for the operating system that he will use, he needs to estimat

Vedmedyk [2.9K]

Using the z-distribution, we have that:

a) A sample of 601 is needed.

b) A sample of 93 is needed.

c) A. Yes, using the additional survey information from part (b) dramatically reduces the sample size.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so $z = 1.96$ .

For this problem, we consider that we want it to be within 4%.

Item a:

The sample size is <u>n for which M = 0.04.</u>

There is no estimate, hence $\pi = 0.5$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.5(0.5)}{n}}$

$0.04\sqrt{n} = 1.96\sqrt{0.5(0.5)}$

$\sqrt{n} = \frac{1.96\sqrt{0.5(0.5)}}{0.04}$

$(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.5(0.5)}}{0.04}\right)^2$

$n = 600.25$

Rounding up:

A sample of 601 is needed.

Item b:

The estimate is $\pi = 0.96$ , hence:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.96(0.04)}{n}}$

$0.04\sqrt{n} = 1.96\sqrt{0.96(0.04)}$

$\sqrt{n} = \frac{1.96\sqrt{0.96(0.04)}}{0.04}$

$(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.96(0.04)}}{0.04}\right)^2$

$n = 92.2$

Rounding up:

A sample of 93 is needed.

Item c:

The closer the estimate is to $\pi = 0.5$ , the larger the sample size needed, hence, the correct option is A.

For more on the z-distribution, you can check brainly.com/question/25404151

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2 years ago