we know that
A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form y/x=k or y=kx
so
we have
a) for x=1 y=0.50--------> y/x=0.50/1------> 0.50
b) for x=2 y=1--------> y/x=1/2-------> 0.50
c) for x=3 y=1.50--------> y/x=1.50/3-----> 0.50
d) for x=5 y=2.50--------> y/x=2.50/5----> 0.50
the value of k is equal to 0.50
so
<span>the relationship forms a direct variation. </span>
the equation is
y=0.50*x
Verify
for x=1
y=0.50*(1)------> y=0.50-----> is correct
for x=2
y=0.50*(2)------> y=1.00-----> is correct
for x=3
y=0.50*(3)------> y=1.50-----> is correct
for x=5
y=0.50*(5)------> y=2.50-----> is correct
Answer:
(x,y) = (2,3)
Step-by-step explanation:
y=5x-7 (i)
-3x-2y= -12
-(3x+2y)= -12
3x+2y= 12 (ii)
By putting the value of y from (i) in (ii)
3x+2(5x-7)=12
3x+10x-14=12
13x=12+14
13x= 26
x = 
x= 2
By putting the value of x in (i)
y= 5(2)-7
y= 10-7
y= 3
(x,y) = (2,3)
309× 29 = 8,961 is totally answer
<span><span><span>15+<span>3t</span></span>−5</span>−<span>8t</span></span><span>=<span><span><span><span><span>15+<span>3t</span></span>+</span>−5</span>+</span>−<span>8t</span></span></span>Combine Like Terms:<span>=<span><span><span>15+<span>3t</span></span>+<span>−5</span></span>+<span>−<span>8t</span></span></span></span><span>=<span><span>(<span><span>3t</span>+<span>−<span>8t</span></span></span>)</span>+<span>(<span>15+<span>−5</span></span>)</span></span></span><span>=<span><span>−<span>5t</span></span>+10</span></span>Answer:<span>=<span><span>−<span>5t</span></span>+<span>10</span></span></span>
