3 years ago

Write the standard equation of a circle with center (-3, 4) (-3, 4) and radius 1.

Mathematics

1 answer:

Neporo4naja [7]3 years ago

3 0

Answer:

The answer is (x+3)^2+(y-4)^2=1

Step-by-step explanation:

The equation is (x-a)^2+(y-b)^2=r^2

In this equation, a and b are the coordinates of a center, and r is radius

Substituting given values, we obtain our answer.

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Answer:

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Step-by-step explanation:

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3 years ago

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$\begin{gathered} -3x^2-24x-13=-13 \\ \text{ Express it as:} \\ 3x^2+24x+26=0 \\ 3x^2+24x=-26 \\ 3(x^2+8x+16)=?-26 \\ 3(x+4)^2=48-26 \\ 3(x+4)^2=22 \end{gathered}$

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1 year ago

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3 years ago

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3 years ago

Write the standard equation of a circle with center (-3, 4) (-3, 4) and radius 1.​

Write the standard equation of a circle with center (-3, 4) (-3, 4) and radius 1.