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vagabundo [1.1K]
3 years ago
15

A pool charges a membership fee of $40 for the summer and $1 for each visit. A different pool charges no membership fee but it c

osts $5 for each visit. How many visits would the two pools cost the same amount? A)40 visits B)10 visits C)5 visits D)they'll never cost the same amount
Mathematics
1 answer:
Cloud [144]3 years ago
4 0

Answer:

B) 10 visits

Step-by-step explanation:

Let the number of visits be x.

Pool A cost: 1x + 40 = x + 40

Pool B cost: 5x

Set the two costs equal and solve for x.

x + 40 = 5x

Subtract 5x from both sides. Subtract 40 from both sides.

-4x = -40

Divide both sides by -4.

x = 10

Answer: B) 10 visits

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Help pls!!!!!!!!!!!!!!!!
Anastaziya [24]

ANSWER.


The correct answer is Option A


EXPLANATION.


The real number

\sqrt{35}=5.916079783


to 9 decimal places.


You can see that the decimals are not repeating, neither will they terminate.



Therefore the real number \sqrt{35} is irrational because, the decimal does not terminate or repeat


Also note that,


\sqrt{35}=\sqrt{5} \times \sqrt{7} .


That is,

\sqrt{35} is a product of two irrational numbers, which still gives an irrational number.

8 0
3 years ago
Infinito álgebra For -2x-9y=-25 and -4x-9y=-23
Levart [38]
-2x -9y = -25
-(-4x -9y =-23)
2x = -2
x = -1

-2(-1) -9y = -25
2 - 9y = -25
-9y = -25 -2
-9y = -27
y = 3
(-1,3)
7 0
3 years ago
Please help!!!!!!!!!!!!!!!!!!!
erastovalidia [21]

Answer:

True,c,b,a

Step-by-step explanation:

Hopes this helped:)

6 0
3 years ago
Simplify the expression. <br><br> (128x^5/ 8x)1/4 <br><br> Enter your answer in the box.
Pachacha [2.7K]
To solve: 
Simplify 128x^5/8x first
16x^4

then divide by 1/4

16x^4•4/1=64x^4

Answer: 64x^4
7 0
3 years ago
Read 2 more answers
Two numbers have a difference of 0.7 and a sum of 1. what are the numbers?
Fofino [41]
<span>In order to determine the value of the numbers, we can set up algebraic equations to solve. For this case, we need to set up two equations since we have two unknown numbers. We do as follows:
 let x = first number and y = second number
 From the problem statement, we set up equations.
 Equation 1 - the numbers have a difference of 0.7
 x - y = 0.7
 Equation 2 - the numbers have a sum of 1
 x + y = 1
 Solving for x and y via substitution method,
 x - y = 0.7
(1-y) - y = 0.7
1 - 2y = 0.7
-2y = 0.7 - 1 = -0.3
y = 0.15 or 3/20
 x - 0.15 = 0.7
x = 0.85 or 17/20
 Thus, the two numbers are 0.15 and 0.85.</span>
6 0
3 years ago
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