Answer:
The x-coordinate of the point changing at ¼cm/s
Step-by-step explanation:
Given
y = √(3 + x³)
Point (1,2)
Increment Rate = dy/dt = 3cm/s
To calculate how fast is the x-coordinate of the point changing at that instant?
First, we calculate dy/dx
if y = √(3 + x³)
dy/dx = 3x²/(2√(3 + x³))
At (x,y) = (1,2)
dy/dx = 3(1)²/(2√(3 + 1³))
dy/dx = 3/2√4
dy/dx = 3/(2*2)
dy/dx = ¾
Then we calculate dx/dt
dx/dt = dy/dt ÷ dy/dx
Where dy/dx = ¾ and dy/dt = 3
dx/dt = ¾ ÷ 3
dx/dt = ¾ * ⅓
dx/dt = ¼cm/s
The x-coordinate of the point changing at ¼cm/s
Answer:
55%
If 1,210 people would buy that type of car again, they were satisfied with it.
The fraction of people who were satisfied would be
.
To find a percentage, we need to divide the top of the fraction by the bottom, then multiply by 100.
1210/2200 is equal to 0.55. This is the decimal form of the fraction, but we need the percentage.
0.55 x 100 is equal to 55.
The answer is 55%
I believe this would be 5x/2x-5
Hope this helps!