This is a combination problem. The approach to this is by using the nCr method, where n is the number of total objects and r is the number of success. For example, if you want to get 3 red out of the total 4, then that would be 4C3. That means,
4C3 = 4!/3!(4 - 3)! = 4 ways
If you want to get 2 green out of the total 6, then that would be 6C2. That means,
6C2 = 6!/2!(6-2)! = 15 ways
Therefore, there are a total of 4+15 = <em>19 ways</em>.
y= mx/z
You isolate the variable by dividing each side by factors that don't contain the variable, which gives you the answer as "mx" as the numerator and "Z" as the denominator.
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Answer:
x=10
Step-by-step explanation:
2x-12 = 18
+12 +12
2x=20
20/2 = 10
Given that:
5π/3
=5/3×180
=240°
This is in the Quadrant III
The value of cot 5π/3 will be given by:
cost θ=1/tan θ
thus
tan θ
=tan 5π/3
=tan 240
=tan (240-180)
=tan 60
using an equilateral triangle with lengths 2 units
then
tan 60=√3/1
tan 60=√3
hence
tan 240=√3
Answer:
y = 3x -18 ( where y = balls sent back by Rudolf; x= balls given to Rudolf)
Step-by-step explanation:
x (Balls given) y( Balls sent back)
8 6 Δy/Δx = (27-6)/(15-8) = 3
15 27
25 57 Δy/Δx = (57-27)/(25-15) = 3
Observing the number sequence shows constant gradient and as such we can use equation of a straight line to relate the two variables.
Using the equation of a straight line we have:
(y-y1)/(x-x1) = (y2-y1)/(x2-x1)
y-6/x-8 = (27-6)/(15-8)
y-6/x-8 = 3
y-6 = 3(x-8)
y-6 = 3x - 24
y = 3x-18
