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kolezko [41]
3 years ago
13

Consider the 20 points of a 4×5 grid. You randomly choose two points from the 20 points. What is the probability that the two po

ints belong to a horizontal or vertical line?
Mathematics
1 answer:
Serhud [2]3 years ago
6 0

Answer:

The probability of both points falling in the same row or column is 7/19, or approximately 37%

Step-by-step explanation:

The easiest way to solve this is to think of it rephrased as "what is the probability that your second point will be in the same row or column as your first point".  With that frame of reference, you can simply consider how many other points are left that do or do not fall in line with the selected one.

After selecting one, there are 19 points left.

The row that the first one falls in will have 3 remaining empty points.

The column will have 4 remaining empty points.

Add those up and you have 7 possible points that meet the conditions being checked.

So the probability of both points falling in the same row or column is 7/19, or approximately 37%

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Which point on the number line is the best approximation for √59?
Elina [12.6K]

Answer:

6^2 = 36

Step-by-step explanation:

The number that best approximates the square of 6 is 36, its actual value. The point so labelled is the appropriate point on the number line.

7 0
3 years ago
HII HELP OK THIS ASAP PLS​
Paha777 [63]

Answer:D

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3 years ago
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At a raffle, 1500 tickets are sold at $2 each. There are four prizes given for $500, $250, $150, and $75. You buy one ticket. Us
wolverine [178]

Answer:

<u>The expected value of every ticket is a loss of $ 1.35</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Number of tickets sold at the raffle = 1,500

Price of each ticket = $ 2

Total prizes = 1 * $ 500 + 1 * $ 250 + 1 * $ 150 + 1 * $ 75

2. Use a probability distribution table to calculate the expected value of your gain. Your expected value is_____ ?

Let's answer the question using a probability distribution for the gains, this way:

  • Probability of 1st prize of $ 498 (500 - ticket) = 1/1,500
  • Probability of 2nd prize of $ 248 (250 - ticket) = 1/1,500
  • Probability of 3rd prize of $ 148 (150 - ticket) = 1/1,500
  • Probability of 4th prize of $ 73 (75 - ticket) = 1/1,500
  • Probability of losing $ 2 (ticket) = 1,496/1,500

Now, we calculate the mean for all the tickets (winners and non-winners), this way:

Expected value = [(1,496 * -2) + (1 * 498) + (1 * 248) + ( 1 * 148) + ( 1 * 73)]/1,500

Expected value = [- 2,992 +498 + 248 + 148 + 73)/1,500

Expected value = -2,025/1,500 = - 1,35

<u>The expected value of every ticket is a loss of $ 1.35</u>

8 0
4 years ago
What is the absolute value of -6?
qaws [65]

Answer:

6

Step-by-step explanation:

The absolute value of a non-negative number is the same number.

Example: The absolute value of 4 is 4.

If a number is negative, its absolute value is the same number, without the negative sign.

Example: The absolute value of -3 is 3.

6 0
3 years ago
Read 2 more answers
A spinner and 6 cards are shown below:
Tems11 [23]

Answer:

1 over 18

Step-by-step explanation:

The spinner has 3 segments and he spun it 1 time.  So, he has a 1 in 3 chance of landing on green.

There are 6 cards so he has a 1 and 6 chance of picking up the yellow card.    

Multiply those and you have 1 over 18

Done!

3 0
3 years ago
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