Answer:
Step-by-step explanation:
One way to determine if the equation has any real solutions is to look at its discriminant. For the equation ax²+bx+c = 0, the discriminant is ...
d = b² -4ac
When the discriminant is negative, both solutions to the quadratic are complex. There are no real solutions in that case.
We can find the discriminant values to be ...
A: d = 2² -4(1)(4) = -12 . . . . no real zeros
B: d = 0² -4(3)(-5) = 60 . . . two real zeros
C: d = 8² -4(-2)(0) = 64 . . . two real zeros
D: d = 10² -4(1)(26) = -4 . . .no real zeros
Expressions A and D have no real zeros.
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<em>Comment on the question</em>
You are given an <em>expression</em>, not an <em>equation</em>. There is no equal sign. Hence, we cannot talk about <em>solutions</em>. We can only talk about <em>zeros</em>, values of x that make the expression have a value of zero.
Answer:
On a recent day, 8 euros were worth $11 and 40 euros were worth $55. Enter an equation of the form y = kx to show the relationship between the number of euros and the value in dollars. First solve k which is the slope so k = ( 55- 11) / ( 40 -8) = 1.375
Y= 1.375x
Step-by-step explanation:
Answer: b) (x - 2)(x + 1)(x + 3)
<u>Step-by-step explanation:</u>
Look at the graph to find the x-intercepts (where the graph crosses the x-axis).
x = 2 x = -1 and x = -3
Now rearrange each of those equation so they are equal to zero:
x - 2 = 0 x + 1 = 0 and x + 3 = 0
Next, combine them (using multiplication):
(x - 2) (x + 1) (x + 3) = 0
Lastly, evaluate the sign of the a-value (coefficient of the polynomial):
Since the right side of the graph goes to POSITIVE infinity, then the a-value is positive.
Order is important in ratios so in this one, it says the ration from GIRLS to BOYS.
We know there are 12 girls and 9 boys so the ratio is B. 12:9
