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3 years ago

You roll a six-sided number cube and flip a coin.What is the probality of rolling a number less than 2 and flipping heads

Mathematics

1 answer:

nalin [4]3 years ago

4 0

Answer:

1 / 12

Step-by-step explanation:

A six - sided coin :

Sample space = (1, 2, 3, 4, 5, 6)

Flipping a number less Than 2

Required outcome = (1)

P(number less Than 2) = required outcome / sole space = 1 / 6

Flipping a head from a coin toss :

Sample space = (H, T)

P(head) = 1 /2

P(number less Than 2 and flipping head) :

= 1/2 * 1 /6

= 1 / 12

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Please help with this

Setler [38]

Answer:

x = 6

Step-by-step explanation:

The scale factor is

28/8 = 7/2

We take the ratio of the larger side over the smaller side

Using ratios we can find the sides

28 21

----- = ---------

8 x

Using cross products

28x = 21*8

28x =168

Divide each side by 28

28x/28 = 168/28

x =6

7 0

3 years ago

30% of 60 is <br><br> 30%of ____ is 60

ololo11 [35]

You know that 3 times 2 is 6 so 30'times 20 equals 60

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3 years ago

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If a plane flies 612 km per hour, approximately how many kilometres will it travel in 13 hours?

zaharov [31]

$612km...........1h \\ x...................13h \\ \\ x=\frac{612*13}{1} \\ \\ \boxed{x=7956km}$

7 0

3 years ago

Read 2 more answers

The following data gives the speeds (in mph), as measured by radar, of 10 cars traveling north on I-15. 76 72 80 68 76 74 71 78

____ [38]

Answer:

71.123 mph ≤ μ ≤ 77.277 mph

Step-by-step explanation:

Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:

$m-t_{a/2,n-1}\frac{s}{\sqrt{n} }$ ≤ μ ≤ $m+t_{a/2,n-1}\frac{s}{\sqrt{n} }$

Where m is the mean of the sample, s is the standard deviation of the sample, n is the size of the sample, μ is the mean speed of all cars, and $t_{a/2,n-1}$ is the number for t-student distribution where a/2 is the amount of area in one tail and n-1 are the degrees of freedom.

the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.

So, if we replace m by 74.2, s by 5.3083, n by 10 and $t_{0.05,9}$ by 1.8331, we get that the 90% confidence interval for the mean speed is:

$74.2-(1.8331)\frac{5.3083}{\sqrt{10} }$ ≤ μ ≤ $74.2+(1.8331)\frac{5.3083}{\sqrt{10} }$

74.2 - 3.077 ≤ μ ≤ 74.2 + 3.077

71.123 ≤ μ ≤ 77.277

8 0

3 years ago

Please i need help.....

Lina20 [59]

Answer:

A.105°

Step-by-step explanation:

Angle at W and V are equal and the angles at T and U are also equal

Hence taking angles at T and U...so as to calculate the value of x

5x + 15 = 3x + 21

5x - 3x = 21 - 15

2x = 6.....hence, x = 3

Then for the angle of VXU;

All angles in a triangle add up to 180°

15(3) + 3(3) + 21 = 75°...then subtract from 180°..so as to obtain angle at VXU

180 - 75 = 105°

7 0

3 years ago