Answer:
0.0016283
Step-by-step explanation:
Given that:
Proportion of defective bulbs, p = 30% = 0.3
Sample size, n = 19 bulbs
Probability that the lot will pass inspection :
P(none of the 19 is defective) Or P(only one of the 19 is defective)
P(none of the 19 is defective) = (1 - p) ^n = (1 - 0.3)^19 ; 0.7^19
0.7^19 = 0.0011398
P(only one of the 19 is defective) :
P(1 defective) * P(18 not defective )
(0.3) * (1 - 0.3)^18
0.3 * 0.7^18
0.3 * 0.001628413597910449 = 0.0004885
Hence,
P(none of the 19 is defective) + P(only one of the 19 is defective)
0.0011398 + 0.0004885) = 0.0016283
Answer:
Step-by-step explanation:
1. 5, 3.5,
,
, -7
2. 10, π ,3.1415, 0, -10
3. 1
, 1.44, 1.4(3), 1.(43), 
Answer:
b.
Step-by-step explanation:
Seats to minutes = 2 to 11:
2/11 = s/m.
When s = 16:
2/11 = 16/m
m = 11*16 / 2
= 176/2
= 88 minutes.
When s = 19:
2/11 = 19 / m
m = 11*19 / 2
m = 209/2
= 104.5 minutes.
I found the dot plots that accompanies this problem.
Based on the plots, the <span>statement that gives is a valid comparison of the number of candies in the bags of the two Brands is:
</span><span>B. The number of candies in the bags from Brand B is greater and less consistent than the number of candies in the bags from Brand A.
Dots in Brand B are scattered and whereas dots in Brand A are not and they are more concentrated between 52 to 55 range. </span>