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lesya [120]
3 years ago
13

If x = 2 work out the value of 4x 2

Mathematics
2 answers:
il63 [147K]3 years ago
8 0
4(2)x2= 8x2=16
16 is the answer!
aleksandrvk [35]3 years ago
5 0

Answer:

16

Step-by-step explanation:

First plug in 2 as the "x" in 4x

so 4 times (2) times (2)

and if you mutiple 4 x 2 you get 8

then 8 times 2 is 16

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Help asap please :(<br><br> Find the surface area of the composite figure.
Liono4ka [1.6K]

Answer:

136 in²

Step-by-step explanation:

8x2=16

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6x2=12

6x2=12

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2x2=4

136 in²

8 0
3 years ago
How can i score best mark uee in 2019?
jolli1 [7]

Answer:

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Simplify and expression for the perimeter of the the rectangle shown.
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Step-by-step explanation:

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6 0
3 years ago
Quadrilateral ABCD is similiar to quadrilateral EFGH. The lengths of the three longest sides in quadrilateral ABCD are 60 feet,
Ivan

Answer:

15 feet

Step-by-step explanation:

Quadrilateral ABCD has a scale facter of 2.5 over the quadrilateral EFGH. The order of ABCD is 60, 40, 30, and x, EFGH has y, z, 12, and 6.

6 times the scale factor of 2.5 is 15, the answer.

7 0
4 years ago
Hi guys, can anyone help me with this triple integral? Many thanks:)
Crank

Another triple integral.  We're integrating over the interior of the sphere

x^2+y^2+z^2=2^2

Let's do the outer integral over z.   z stays within the sphere so it goes from -2 to 2.

For the middle integral we have

y^2=4-x^2-z^2

x is the inner integral so at this point we conservatively say its zero.  That means y goes from -\sqrt{4-z^2} and +\sqrt{4-z^2}

Similarly the inner integral x goes between \pm-\sqrt{4-y^2-z^2}

So we rewrite the integral

\displaystyle \int_{-2}^{2} \int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}} \int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dx \; dy \; dz

Let's work on the inner one,

\displaystyle\int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dz

There's no z in the integrand, so we treat it as a constant.

=(x^2+xy+y^2)z \bigg|_{z=-\sqrt{4-y^2-z^2}}^{z=\sqrt{4-y^2-z^2}}

So the middle integral is

\displaystyle\int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}}2(x^2+xy+y^2)\sqrt{4-y^2-z^2} \ dy  

I gotta go so I'll stop here, sorry.

7 0
3 years ago
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