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3 years ago

I need help with this. Thanks I need to find the degree

Mathematics

1 answer:

scoundrel [369]3 years ago

3 0

Answer:

119.05°

Step-by-step explanation:

In general, the angle is given by ...

θ = arctan(y/x)

Here, that becomes ...

θ = arctan(9/-5) ≈ 119.05°

_____

<em>Comment on using a calculator</em>

If you use the ATAN2( ) function of a graphing calculator or spreadsheet, it will give you the angle in the proper quadrant. If you use the arctangent function (tan⁻¹) of a typical scientific calculator, it will give you a 4th-quadrant angle when the ratio is negative. You must recognize that the desired 2nd-quadrant angle is 180° more than that.

It may help you to consider looking at the "reference angle." In this geometry, it is the angle between the vector v and the -x axis. The coordinates tell you the lengths of the sides of the triangle vector v forms with the -x axis and a vertical line from that axis to the tip of the vector. Then the trig ratio you're interested in is ...

Tan = Opposite/Adjacent = |y|/|x|

This is the tangent of the reference angle, which will be ...

θ = arctan(|y| / |x|) = arctan(9/5) ≈ 60.95°

You can see from your diagram that the angle CCW from the +x axis will be the supplement of this value, 180° -60.95° = 119.05°.

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<h3>What is the domain and range of the function?</h3>

The domain of a function is defined as the set of all the possible input values that are valid for the given function.

The range of a function is defined as the set of all the possible output values that are valid for the given function.

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The range of a relation is the set of values of the dependent variable for a defined function.

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-5 < x ≤ 1 ------ (-5, 1] in interval notation

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The range

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Learn more about the domain and range of the function:

brainly.com/question/2264373

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