Volume of the sphere: [4/3]π (r^3) = [4/3]π(5a)^3 = [4/3]π*125a^3 =
Volume of the cone: [1/3]π(r^2)H = [1/3]π(3a)^2 * H = 3πa^2 * H
Volumen of the sphere = Volumen of the cone =>
[4/3]π*125a^3 = 3πa^2 * H => H = [500/9]a = 55.55 a
Answer:
The weight of the enlarged paperweight is ![1.2\ lb](https://tex.z-dn.net/?f=1.2%5C%20lb)
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its volumes (or its weights) is equal to the scale factor elevated to the cube
Let
z-----> the scale factor
x ----> the enlarged paperweight weight
y ----> the original paperweight weight
![z^{3}=\frac{x}{y}](https://tex.z-dn.net/?f=z%5E%7B3%7D%3D%5Cfrac%7Bx%7D%7By%7D)
we have
![z=2](https://tex.z-dn.net/?f=z%3D2)
![y=0.15\ lb](https://tex.z-dn.net/?f=y%3D0.15%5C%20lb)
substitute and solve for x
![2^{3}=\frac{x}{0.15}](https://tex.z-dn.net/?f=2%5E%7B3%7D%3D%5Cfrac%7Bx%7D%7B0.15%7D)
![x=2^{3}(0.15)=1.2\ lb](https://tex.z-dn.net/?f=x%3D2%5E%7B3%7D%280.15%29%3D1.2%5C%20lb)
Answer:
Step-by-step explanation:
The discriminant is what's under the square root sign in the quadratic equation. The equation for the discriminant is
, where b is the coefficient of x, a is the coefficient of
, and c is the number with no variable attatched to it. If we plug in the numbers (
) it gives you 241, which is the discriminant. Since 241 is more than zero, it has 2 zeros. If the discriminant was 0, there'd be 1 zero, and less then zero there would be zero zeros.
11, because if you count the numbers between 28 and 39. It would be 11.☺️
32 people at only pancakes.
162 people ate at the resturant that morning.
92 people didn't eat eggs.