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katrin2010 [14]
3 years ago
15

Complete the missing value in the solution to the equation.

Mathematics
1 answer:
OverLord2011 [107]3 years ago
8 0
Y= 5

5(8) - 2(5)

40 - 10 = 30
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What are the solutions of the equation x^4 + 6x^2 + 5 = 0? Use u substitution to solve.
Radda [10]

Answer:

second option

Step-by-step explanation:

Given

x^{4} + 6x² + 5 = 0

let u = x², then

u² + 6u + 5 = 0 ← in standard form

(u + 1)(u + 5) = 0 ← in factored form

Equate each factor to zero and solve for u

u + 1 = 0 ⇒ u = - 1

u + 5 = 0 ⇒ u = - 5

Change u back into terms of x, that is

x² = - 1 ( take the square root of both sides )

x = ± \sqrt{-1} = ± i ( noting that \sqrt{-1} = i ), and

x² = - 5 ( take the square root of both sides )

x = ± \sqrt{-5} = ± \sqrt{5(-1)} = ± \sqrt{5} × \sqrt{-1} = ± i\sqrt{5}

Solutions are x = ± i and x = ± i\sqrt{5}

3 0
2 years ago
Find the particular solution to y'=2sin(x) given the general solution is y=C-2cos(x) and the initial condition y(pi/3)=1
mezya [45]

ANSWER

The particular solution is:

y=2-2 \cos(x)

EXPLANATION

The given Ordinary Differential Equation is

y'=2 \sin(x)

The general solution to this Differential equation is:

y=C-2 \cos(x)

To find the particular solution, we need to apply the initial conditions (ICs)

y( \frac{\pi}{3} ) = 1

This implies that;

C-2 \cos( \frac{\pi}{3} ) = 1

C-2( \frac{1}{2} )= 1

C-1= 1

C= 1 + 1 = 2

Hence the particular solution is

y=2-2 \cos(x)

4 0
3 years ago
Plssssss helpppp !!<br> tysmmmm
Elza [17]

I think that the answer would be two triangles.

6 0
3 years ago
Help me please, not very good at math. Thank u:)
ozzi

Answer:

76cm^2

Step-by-step explanation:

Separate the shape into two different rectangles. Then add the area of the rectangles together.

4 x 4 = 16

6 x 10 = 60

16 + 60 = 76

8 0
2 years ago
Read 2 more answers
if one face of a cube has an area of 6.75 square inches , what is the surface area of the entire cube ?​
Travka [436]

Answer:

40.5

Step-by-step explanation:

a cube has 6 faces so 6.75 x 6 = 40.5

3 0
3 years ago
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