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Debora [2.8K]
3 years ago
12

Find the 13th term in the following arithmetic sequence 2, 10, 18, 26, ...

Mathematics
2 answers:
Delvig [45]3 years ago
4 0

Answer:

a(13) = 98

Step-by-step explanation:

<em>a(n) = a1 + (n-1) d</em>

a1 would be the original term, 2

since you are looking for the 13th term a(n) and n is 13

a(13) = 2 + (13-1) d

d would be the difference between each term, 8

a(13) = 2 + (13-1) 8

Now solve

a(13) = 2 + 12 * 8

a(13) = 2 + 96

a(13) = 98

NARA [144]3 years ago
3 0

Answer:

Find the 13th term in the following arithmetic sequence

2, 10, 18, 26 ...192 is the 13th term

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A union of restaurant and foodservice workers would like to estimate the mean hourly wage, μ, of foodservice workers in the U.S.
pav-90 [236]

Answer:

n=(\frac{1.960(2.25)}{0.35})^2 =158.76 \approx 159

So the answer for this case would be n=159 rounded up to the nearest integer

Step-by-step explanation:

Assuming this complete question: A union of restaurant and foodservice workers would like to estimate the mean hourly wage, , of foodservice workers in the U.S. The union will choose a random sample of wages and then estimate using the mean of the sample. What is the minimum sample size needed in order for the union to be 95% confident that its estimate is within $0.35 of ? Suppose that the standard deviation of wages of foodservice workers in the U.S. is about $2.15 .

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=2.25 represent the population standard deviation

n represent the sample size  

Solution to the problem

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

And on this case we have that ME =0.35 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got z_{\alpha/2}=1.960, replacing into formula (b) we got:

n=(\frac{1.960(2.25)}{0.35})^2 =158.76 \approx 159

So the answer for this case would be n=159 rounded up to the nearest integer

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2 years ago
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Answer:

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Step-by-step explanation:

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hope this helps, have a good day.

5 0
1 year ago
A poll that does not attempt to generate a random sample, but instead invites people to volunteer to participate is called:_____
Helga [31]

Answer:

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Step-by-step explanation:

A poll that does not attempt to generate a random sample, but instead invites people to volunteer to participate is called - self selection sampling.

Self-selection sampling is a sampling method where researchers allow the people or individuals, to choose to take part in research on their own accord.

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