Question

Defines y as a function of x x squared plus y squared equals 36

Answer 1

$\text{Given that: \: } {x}^{2} + {y}^{2} = 36$

${x}^{2} + {y}^{2} = 36 \\ \\ {y}^{2} = 36 - {x}^{2} \\ \\ y = \pm \sqrt{36 - {x}^{2} }$

$\text{Thus, y as a function of x is given as:} \\ \\ \boxed{ \red{ y = f(x) = \pm \: \sqrt{36 - {x}^{2} }} }$