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3 years ago

If 2x+4=8, what is 9x?

Mathematics

2 answers:

marissa [1.9K]3 years ago

7 0

Answer:

hope it will be helpful to you

Nataliya [291]3 years ago

3 0

Answer:

..have a great day ahahahahah

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You plant a tree that is 3636 inches tall. After one year, the tree is 4343 inches tall. Which expression describes the percent

damaskus [11]

The expression should be 3636+h

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3 years ago

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A 17- foot ladder is placed against a vertical wall of a building with the bottom of the ladder standing on level ground 11 feet

Hunter-Best [27]

Answer:

y= $\sqrt{168}$ or about 12.96 ft

Step-by-step explanation:

11^2+y^2=17^2

y^2=168

y= $\sqrt{168}$ or about 12.96 ft

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2 years ago

I need help with this problem anybody, please

myrzilka [38]

Answer:

It's B. 42 divided by 6 = 7

Step-by-step explanation:

A quotient is the result you get when you divide, and only one of them is division.

Hope this helped lots and lots,

Sincerely, me

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3 years ago

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If the work required to stretch a spring 2 ft beyond its natural length is 6 ft-lb, how much work is needed to stretch it 6 in.

mel-nik [20]

Answer:

0.375 feet-lb

Step-by-step explanation:

We have been given that the work required to stretch a spring 2 ft beyond its natural length is 6 ft-lb. We are asked to find the work needed to stretch the spring 6 in. beyond its natural length.

We can represent our given information as:

$6=\int\limits^2_0 {F(x)} \, dx$

We will use Hooke's Law to solve our given problem.

$F(x)=kx$

Substituting this value in our integral, we will get:

$6=\int\limits^2_0 {kx} \, dx$

Using power rule, we will get:

$6=\left[ \frac{kx^2}{2} \right ]^2_0$

$6=\frac{k(2)^2}{2}-\frac{k(0)^2}{2}$

$6=\frac{4k}{2}-0\\\\k=3$

We know that 6 inches is equal to 0.5 feet.

Work needed to stretch it beyond 6 inches beyond its natural length would be $\int\limits^{0.5}_0 {kx} \, dx =\int\limits^{0.5}_0 {3x} \, dx$

Using power rule, we will get:

$\int\limits^{0.5}_0 {3x} \, dx = \left [\frac{3x^2}{2}\right]^{0.5}_0$

$\frac{3(0.5)^2}{2}-\frac{3(0)^2}{2}\Rightarrow \frac{3(0.25)}{2}-0=\frac{0.75}{2}=0.375$

Therefore, 0.375 feet-lb work is needed to stretch it 6 in. beyond its natural length.

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3 years ago

HEEEELLLLPPPPPPPPP !!!!

Radda [10]

Answer:

Step-by-step explanation:

Common difference = 5

a₁ = 24

a₆ = a₁ + (6-1)5 = 49

7 0

3 years ago