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aev [14]
3 years ago
10

If 2x+4=8, what is 9x?

Mathematics
2 answers:
marissa [1.9K]3 years ago
7 0

Answer:

hope it will be helpful to you

Nataliya [291]3 years ago
3 0

Answer:

..have a great day ahahahahah

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The product of a number and 9, increased by 4, is 58. Find the number.
diamong [38]
9x + 4 = 58
9x = 54
x = 6

The number is 6.
4 0
3 years ago
Ms. Golding managed to get discount tickets to a BTS concert. At the concert venue, a hot dog costs $4 each, while bottles of so
konstantin123 [22]

Each hot dog is x, and costs $4. Each soda is y, and costs $3.

A.

4x + 3y = 33

B.

4x + 3y = 33

4 * 3 + 3y = 33

12 + 3y = 33

3y = 21

y = 7

7 bottles of soda.

8 0
3 years ago
cos (x/2) = -sqrt2/2 in (0,360) looking for two values ?? Can someone please help me I can’t seem to figure out how to solve thi
ValentinkaMS [17]

Answer:

135° and 225°

Step-by-step explanation:

basically you want to find the value of x between 0 and 360 in this equation

cos x/2 = -(√2)/2

assume x/2 as n, so

cos n = -(√2)/2

n = 45°

then remember the quadrant system

0-90 1st quadrant, all is POSITIVE

90-180 2nd quadrant, only SIN has positive value

180 - 270 3rd quadrant, only TAN has positive value

270 -360 4th quadrant, only COS positive here.

so if you try to find negative value look into 2nd and 3rd quadrant that related 45° to x-axis (0°or 180°)

so the value of x is

180 - 45 = 135° (2nd quadrant) and

180 + 45° = 225° (3rd quadrant)

8 0
2 years ago
If two objects travel through space along two different curves, it’s often important to know whether they will collide. (Will a
galina1969 [7]

Answer:

<em>Both objects collide at t=3 in the point  <9,9,9></em>

Step-by-step explanation:

<em>Collision Of Moving Objects </em>

Two objects can describe different trajectories in the space. Those trajectories can intersect in one or more points but it doesn't mean they collide. Collision occurs if they are in the same position at the same time. If we know the positions as a function of time of each object, we could try so find if, for a given time, they are in the same position.

The positions of two object are given as

r1(t)=

r2(t)=

Let's find out if there is at least one value of t that makes both positions to be the same. We can try by equating one of the three coordinates and testing if the value of t make both have the same x,y,z coordinate. Let's try equating the x-components of both

t^2=4t-3

Rearranging

t^2-4t+3=0

Factoring

(t-1)(t-3)=0

We found two solutions

t=1,\ t=3

for t=1 the x-coordinates are

x1=t^2=1

x2=4t-3=1

For t=3

x1=t^2=9

x2=4t-3=9

Now we'll test both values in the y-coordinates

y1=7t-12

y2=t^2

For t=1

y1=-5

y2=1

Thus they don't collide at t=1. Let's try t=3

y1=7(3)-12=9

y2=3^2=9

Now let's try the z-coordinate for t=3

z1=t^2=9

z2=5t-6=9

Since the three coordinates match, we can say both objects collide at t=3 in the point  <9,9,9>

6 0
3 years ago
Distinguish between expressions and equations algebraically by providing an example of an algebraic expression and an example of
Morgarella [4.7K]
X^3-2x is an algebraic expression.  Note that there is NO "=" sign here.

x^4 + 4x^2 + 4 = 0 is an algebraic equation.  Note the presence of an "=" sign.
7 0
3 years ago
Read 2 more answers
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