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3 years ago

6

Represent fractional percents greater than 100%

2 answers:

Paladinen [302]3 years ago

7 0

Answer:

4/3 6/4 7/2

Step-by-step explanation:

these are all more than 100%

d1i1m1o1n [39]3 years ago

5 0

2/1 is 200% hope I understood this right, if not messages me and I’ll change my answer

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Can you help me please !

Bezzdna [24]

Answer:

Square root of 7 minus 2 equals x.

Step-by-step explanation:

X is irrational soooo

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3 years ago

The question is the photo

Readme [11.4K]

For this question you can say:
5/9( °F - 32) = -10 °C
so now you should solve the equation:
5F/9 - 160/9 = -10
⇒ 5F/9 = -10 + 160/9 ⇒ 5F/9 = -90/9 + 160/9 ⇒ 5F/9 = 70/9 ⇒ now you can multiply both sides of the equation by 9 so you will have:
5F = 70 ⇒ F = 14 ° F :)))
i hope this is helpful
have a nice day

6 0

3 years ago

Kelvin saves $60 a day. Al saves $90 a day. How many times Kelvin's savings are Al's savings?

vaieri [72.5K]

How many times Kevin's savings are al's savings is 30 more

5 0

3 years ago

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Can anyone help me???

lbvjy [14]

Answer:

I think it's J.

Step-by-step explanation:

I don't know how to explain it. •-• Sorry!

7 0

3 years ago

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a pyramid whose altitude is 5ft weighs 800lbs. at what distance from its vertex must it be cut by a plane parallel to its base s

slavikrds [6]

A structure which has a square base and four triangular sides meeting at a point is called pyramid.

At distance of 3.97 feet from its vertex , pyramid is cut by plane so that the two solids of equal weight will be formed.

<u>It is assumed that weight of pyramid is proportional to its volume.</u>

So, $w = k V$ , where V is volume of original pyramid and v is volume of small pyramid and k is constant.

Let us consider that at h distance, pyramid is cut from its vertex. So a small pyramid is also formed.

Assume that base area of original pyramid is A and base of small pyramid is a.

Volume of original pyramid is, $V= \frac{1}{3} *A* 5$

So, weight of original pyramid, $W = k *(\frac{1}{3} *A* 5) = 800$

Volume of small pyramid is, $v = \frac{1}{3}* a* h$

So, weight of small pyramid, $w = k*(\frac{1}{3}* a* h)=400$

<u>Since, base and height of small pyramid and original pyramid are in proportion.</u>

So, $\frac{a}{A} = (\frac{h}{5}) ^{2}$

$a = (\frac{h}{5} )^{2}A$

Substituting value of a in equation $k*(\frac{1}{3}* a* h)=400$

So, $k*(\frac{1}{3}* \frac{h^{2} }{25}A * h)=400$

$(k*\frac{1}{3}* A*5)*\frac{1}{5} *\frac{h^{2} }{25} * h)=400$

Since, $(k *\frac{1}{3} *A* 5) = 800$ , substitute in above equation.

So, $800*\frac{h^{3} }{125}=400\\\\h^{3}=\frac{125}{2}\\\\h=\sqrt[\frac{1}{3} ]{62.5}\\\\h=3.97 feet$

Learn more:

brainly.com/question/17950304

6 0

2 years ago

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