3 years ago

HELP PLEASE THIS IS DUE SOON

Mathematics

2 answers:

AlekseyPX3 years ago

7 0

Answer: true

Step-by-step explanation:

gavmur [86]3 years ago

6 0

I think it’s true . but lol who know

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How many different committees can be formed from 99 teachers and 3434 students if the committee consists of 33 teachers and 22

xenn [34]

There are 47,124 different committees you can select.

Explanation:
The number of combinations of 9 teachers taken 3 at a time is given by
 $_9C_3=\frac{9!}{3!6!}=84$ 

The number of combinations of 34 students taken 2 at a time is given by
 $_{34}C_2=\frac{34!}{2!32!}=561$ 

Together this makes 84*561 = 47124 combinations.

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Answer:

Step-by-step explanation:

You don't need to simplify 4/7 because you can't divide 4 and 7 to a same number. I don't necessarily know what you mean by simplifying.

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