Okay, first, given the equation, we need to find out what the radius of the circle is. Let us state the general equation of a circle:

Where

is the centre of the circle. In this case, we don't need to know the centre. Just the radius.
Let us start by converting the equation into standard for, which I typed above. Divide both sides by 81.

Great! We now know the radius of the circle. It is

because it is the bottom fraction. Now we know that the radius is 9.
So now lets input this into the area of circle formula:
Now we insert our radius.
You can convert that into a decimal if you wish.
Hope this helped!
~Cam943, Moderator
uhm I can't help with that... sorry
C) Ther is one outliner , indicating an abnormally large number of books were rented out on that day
Answer:
![f(x) = 2[\frac{3^x}{9}] + 2](https://tex.z-dn.net/?f=f%28x%29%20%3D%202%5B%5Cfrac%7B3%5Ex%7D%7B9%7D%5D%20%2B%202)

Step-by-step explanation:
Given


Required
Remove the h component
In a function, the h component is highlighted as:

So, we have:

Split the exponents using the following law of indices:



![f(x) = 2[\frac{3^x}{9}] + 2](https://tex.z-dn.net/?f=f%28x%29%20%3D%202%5B%5Cfrac%7B3%5Ex%7D%7B9%7D%5D%20%2B%202)
<em>The h component has been removed</em>

Split the exponent using the following law of indices

So, we have:

Express 4^2 as 16

Divide 16 by 2

The y intercept is the y value determined when x = 0
y = -0 - 5
y = - 5
The y intercept is (0,-5)
The x intercept is where y = 0
0 = -x - 5
5= -x
x = - 5
The x intercept is (- 5, 0)