Answer:Add 4.3x to both sides of the equation.
Step-by-step explanation:
The given equation is expressed as
3.7x - 18 = - 4.3x - 34
The main aim is to solve for x and x is on the left hand side and the right hand side of the equation. So the most efficient step would be to make all the terms containing x to be on the left hand side of the equation and the constants to be on the right hand side of the equation.
Therefore, the most efficient first step to solve for x in the equation would be
Add 4.3x to both sides of the equation.
Sorry mate, I can help with 8.) and 9.)
8.) angle T=180-(21+35)
T=180-56
T=124
Angle V=124
Triangle TUV is an isosceles triangle therefore, it has two equal sides and two equal angles.
9.) Angle WSV=21 degree
Triangle TSV is an isosceles triangle therefore, it has two equal sides and two equal angles.
TSV=21+21=42 degree
Had to run, can’t do rest. Hopefully, this helped a bit. Good luck.
The temperature (in k) at which the density of this liquid will be equal to 1.183 g/cm³ is; 639.6 K
<h3>How to find the temperature from density?</h3>
We are given the formula for density as;
D = 1.246 g/cm³/(1 + 8.324 * 10⁻⁵ K⁻¹ × T)
Where D is density and T is absolute temperature (In K).
If we want a density of 1.183 g/cm³, then we have;
1.183 = = 1.246 g/cm³/(1 + 8.324 * 10⁻⁵ K⁻¹ × T)
Cross multiply to get;
1.183 + (1.183 * 8.324 * 10⁻⁵ * T) = 1.246
1.183 + 0.985 * 10⁻⁴T= 1.246
0.985 * 10⁻⁴T = 1.246 - 1.183
T = 0.063/( 0.985 * 10⁻⁴)
T = 639.6 K
Read more about Temperature and Density at; brainly.com/question/17231176
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Answer:
0 tests
Yes, this procedure is better on the average than testing everyone, it makes it less cumbersome.
Step-by-step explanation:
Given the information:
Let P be the probability that a randomly selected individual has the disease = 0.1. N individuals are randomly selected, thereafter, blood samples of each person would be tested after combining all specimens. Should in case one person has the disease then it yields a positive result and test should be set for each person.
Let Y be number tests
For n = 3 there are two possibilities. If no one has the disease then the value is 1 otherwise the value is 4, here P = 0.1
Therefore, for Y = 1
P(Y-1) = P(no one has disease)
= 0.9³
= 0.729
If Y = 4
P(Y-4) = 1-P(y = 1)
= 1 - 0.729 = 0.271
The expected number of tests using this formular gives
E(Y) = 1×0.729 + 4×0.271
E(Y) = 0
