
x = 2
<em>right</em><em> </em><em>option</em><em> </em><em>is</em><em> </em>(E).
Step-by-step explanation:
f(x) = x³ - 3x² + 12 in interval [-2, 4]
{taking f'(x) by doing derivative of f(x)}
f'(x) = 3x² - 6x
.•. f'(x) = 0
0 = 3x² - 6x
0 = 3x(x - 2)
0 = x - 2
x = 2
Step-by-step explanation:
I'll do the first problem as an example.
∠P and ∠H both have one mark. That means they're congruent.
∠T and ∠G both have two marks. So they're congruent.
∠W and ∠D both have three marks. So they're congruent.
So we can write a congruence statement:
ΔPTW ≅ ΔHGD
We can write more congruence statements by rearranging the letter, provided that corresponding pairs have the same position (P is in the same place as H, etc.). For example:
ΔWPT ≅ ΔDHG
ΔTWP ≅ ΔGDH
Answer:
0.8
Step-by-step explanation:
A: P(1) = .6, P(2) = .5, P(1 and 2) = .3
P(1 or 2) = P(1) + P(2) - P(1 and 2) .6 + .5 - .3 = 0.8
Answer:
0.683
Step-by-step explanation:
We have to find P(-1<z<1).
For this purpose, we use normal distribution area table
P(-1<z<1)=P(-1<z<0)+(0<z<1)
Using normal area table and looking the value corresponds to 1.0, we get
P(-1<z<1)=0.3413+0.3413
P(-1<z<1)=0.6826
Rounding the answer to three decimal places
P(-1<z<1)=0.683
So, 68.3% of the z-scores will be between -1 an 1.
Answer: the 3
Step-by-step explanation:
It goes ones, tens, hundreds, thousands, etc. You round the 3 (down, less than 5) because that is in the hundreds place.