Answer:
The answer to the first question is: 9 4/21
The answer to the second question is: B.) 24 14/27
I hope this helps you! :D
Answer:
1
Step-by-step explanation:
Probability is given by number of possible outcomes ÷ number of total outcomes
The time commuting between home and work is 6mi
Probability (the engineer is at least 2mi from home) means that the engineer is either 2mi from home or more than 2mi from home
Probability (the engineer is 2mi from home) = 2/6
Probability (the engineer is more than 2mi from home) = 1 - 2/6 = (6-2)/6 = 4/6
Probability (the engineer is at least 2mi from home) = 2/6 + 4/6 = 6/6 = 1
You have to add AB and for BC you have to add it then you get your answer
I pretty sure the answer is 134217728000000000000/17
2^2x=5^x−1
Take the log pf both sides:
ln(2^2x) = ln(5^x-1)
Expand the logs by pulling the exponents out:
2xln(2) = (x-1)ln(5)
Simpligy the right side:
2xln(2) = ln(5)x - ln(5)
Now solve for x:
Subtract ln(5)x from both sides:
2xln(2) - ln(5)x = -ln(5)
Factor x out of 2xln(2)-ln(5)x
x(2ln(2) - ln(5)) = -ln(5)
Divide both sides by (2ln(2) - ln(5))
X = - ln(5) / (2ln(2) - ln(5))
