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zhannawk [14.2K]
3 years ago
10

WILL MARK BRAINLIEST PLEASE HELP!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Alja [10]3 years ago
3 0

Answer:

i cant draw on dis thing sorry but draw a square with circles on two parallel lines? they take up 1 thumb of space

Step-by-step explanation:

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Please Help me Please Please the question and options are in the picture
Lapatulllka [165]

If you eliminate the parentheses, then add mq, you have

... y - p + mq = mx

Then dividing by m gives you the equation for x:

... x = (y - p + mq)/m

3 0
3 years ago
Hassan just accepted a job at a new company where he will make an annual salary of
stira [4]

Step-by-step explanation:

$68 000 × 8 years

= $544 000

$1 500 × 8 years

= $12 000

$544 000 + $12 000

= $556 00

4 0
3 years ago
What 2 over 3 times 3 over 4
maria [59]
It's 6/12 then 1/2. Good luck
3 0
3 years ago
Read 2 more answers
According to Reuters, a survey undertaken by the National Center for Health Statistics revealed that about 25% of U.S. household
ddd [48]

Answer:

a) P=0.8

b) P=0.67

c) P=0.05

d) P=0.33

e) P=0.45

Step-by-step explanation:

a. What is the probability that the household has only a cell phone and has high-speed Internet?

This probability is stated in the question: "Suppose of U.S. households having only a cell phone, 80% have high-speed Internet", so the probability is P=0.8.

P(C\&I)=0.8

b. What is the probability that the household has only a cell phone or has high-speed Internet?

This probability is equal to the sum of the probability of having only a cell phone and the probability of having high-speed internet, less the probability of having both (to avoid counting this household twice).

P(C\,orI\,)=P(C)+P(I)-P(C)*P(I|C)=0.25+0.65-(0.25*0.8)=0.25+0.62-0.20=0.67

c. What is the probability that the household has only a cell phone and does not have high-speed Internet?

This is equal to the probability of not having high-speed internet given that it has a cell phone (complementaty of the proability of Point (a)) multiplied by the probability of having a cell phone.

P(C\&\bar I)=P(\bar I|C)*P(C)=(1-P(\I|C))*P(C)=(1-0.8)*0.25 = 0.2*0.25 = 0.05

d. What is the probability that the household does not have just a cell phone and does not have high-speed Internet?

This probability is complementary of the one calculated in Point (c).

P(\bar C \,or\, \bar I)=1-P(C\, or\,I)=1-0.67=0.33

e. What is the probability that the household does not have just a cell phone and does have high-speed Internet?

This is equal to the probability of having high-speed internet less the probability it has both (cell phone and internet).

P(\bar C\&I)=P(I)-P(I|C)*P(C)=0.65-0.8*0.2=0.65-0.2=0.45

7 0
4 years ago
Please answer and explain thanksss
Ostrovityanka [42]

Answer:

81000000

Step-by-step explanation:

bracket one

3^2 = 9

9^2 = 81

bracket two

10^3 = 1000

1000^2 = 1000000

81 × 1000000 = 81,000,000

im not very good at explaining but ive tried to break it into parts just to make it a bit simpler to understand :)

4 0
3 years ago
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