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hram777 [196]
3 years ago
9

A company sells widgets. The amount of profit, y, made by the company, is related to the selling price of each widget, x, by the

given equation. Using this equation, find out the maximum amount of profit the company can make, to the nearest dollar. y=-29x^2+1388x-10040
Mathematics
1 answer:
kenny6666 [7]3 years ago
5 0

Given:

The amount of profit, y, made by the company, is related to the selling price of each widget, x, by the given equation

y=-29x^2+1388x-10040

To find:

The maximum amount of profit the company can make, to the nearest dollar.

Solution:

If a quadratic equation is f(x)=ax^2+bx+c, then the vertex is

Vertex=\left(-\dfrac{b}{2a},f(-\dfrac{b}{2a})\right)

If a>0, then vertex is the minimum point and if a<0, then the vertex is the maximum point.

We have,

y=-29x^2+1388x-10040

Here, a=-29,b=1388, c=-10040. Clearly, a<0. So, the vertex is the point of maxima.

-\dfrac{b}{2a}=-\dfrac{1388}{2(-29)}

-\dfrac{b}{2a}=-\dfrac{1388}{-58}

-\dfrac{b}{2a}\approx 23.931

Putting x=23.931 in the given equation, we get

y=-29(23.931)^2+1388(23.931)-10040

y=-16608.09+33216.228-10040

y=6568.138

The vertex is at (23.931,6568.138).

Therefore, the maximum profit is $6568.138 when x=23.931.

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