Step-by-step explanation:
3/8 = 0.375
5/8 = 0.625
4.375 - 1.625
= 2.75
Step 1: Find f'(x):
f'(x) = -6x^2 + 6x
Step 2: Evaluate f'(2) to find the slope of the tangent line at x=2:
f'(2) = -6(2)^2 + 6(2) = -24 + 12 = -12
Step 3: Find f(2), so you have a point on y=f(x):
f(2) = -2·(2)^3 + 3·(2)^2 = -16 + 12 = -4
So, you have the point (2,-4) and the slope of -12.
Step 4: Find the equation of your tangent line:
Using point-slope form you'd have: y + 4 = -12 (x - 2)
That is the equation of the tangent line.
If your teacher is picky and wants slope-intercept, solve that for y to get:
y = -12 x + 20
Answer:

Step-by-step explanation:
From the table given in the question,
x y Difference Ratio
1 12 - -
2 36 36-12 = 24 
3 108 108-36 = 72 
4 324 324-108 = 216 
5 972 972-324 = 648 
There is a common ratio of 3 in each successive term.
Therefore, data given in the table will represent an exponential function.

For a point 

------(1)
For another point of the table
,

--------(2)
Equation (2) divided by equation (1)


From equation (1),


Therefore, exponential function will be,

Given the next quadratic function:

to sketch its graph, first, we need to find its vertex. The x-coordinate of the vertex is found as follows:

where <em>a</em> and <em>b</em> are the first two coefficients of the quadratic function. Substituting with a = 2 and b = 3, we get:

The y-coordinate of the vertex is found by substituting the x-coordinate in the quadratic function, as follows:

The factorization indicates that the curve crosses the x-axis at the points (-2, 0) and (1/2, 0). We also know that the curve crosses the y-axis at (0,-2). Connecting these points and the vertex (-0.75, -3.125) with a U-shaped curve, we get: