Let <em>w</em> be the wind speed and <em>p</em> the plane's speed in still air.
Flying against the wind, the plane has velocity
<em>p</em> - <em>w</em> = 390 mi/h
and flying with it, it has
<em>p</em> + <em>w</em> = 470 mi/h
Add the two equations together to eliminate <em>w</em> and solve for <em>p</em> :
(<em>p</em> - <em>w</em>) + (<em>p</em> + <em>w</em>) = 390 mi/h + 470 mi/h
2<em>p</em> = 860 mi/h
<em>p</em> = 430 mi/h
Subtract them to eliminate <em>p</em> and solve for <em>w</em> :
(<em>p</em> - <em>w</em>) - (<em>p</em> + <em>w</em>) = 390 mi/h - 470 mi/h
-2<em>w</em> = -80 mi/h
<em>w</em> = 40 mi/h
The answer is 23,520 and hi there ! :]
Answer:
Radius AC=12
Step-by-step explanation:
AB is a tangent to circle c so the tangent AB is perpendicular to the radius at A.
Then triangle ABC is right triangle at A.
So by Pythagoras theorem,
CB^2=AB^2 + AC^2
37^2= 35^2 + AC ^2
1369=1225 + AC^2
AC^2= 1369-1225= 144
AC=radical AC^2 =radical 144=12
Hope this helps...
(Note: ^ means power)
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Answer:
Step-by-step explanation:
We can solve this system using substitution.
In this case, we can substitute 7-3y for x, as they are of equal value.
Therefore...
Subtract 14 from both sides:
Divide both sides by -9
Now, substitute 2 for y to solve for x:
Therefore the solution to this system of equations is:
