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3 years ago

Asappp please . Explain

Mathematics

2 answers:

ser-zykov [4K]3 years ago

8 0

Answer: D: 2 1/2

Step-by-step explanation:

LUCKY_DIMON [66]3 years ago

8 0

The answer is D. 5/2 is equal to 2 wholes and a half making it 2 and 1/2

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Adam was packing up his toys he managed to squeeze 52 toys into a box if adam filled 92 boxes how many toys did he pack total

cluponka [151]

If 52 toys fit into a box and there are 92 boxes then the total toys would be 52 x 92 = 4,784

3 0

3 years ago

2.85 as a mixed number

WARRIOR [948]

The number 2.85 can be writen using the fraction 285/100 which is equal to 57/20 when reduced to lowest terms.
It is also equal to 2 17/20 when writen as a mixed number.
You can use the following approximate value(s) for this number:57/20 =~ 2 6/7 (if you admit a error of 0.250627%)2.85 =~ 2 5/6 (if you admit a error of -0.584795%)2.85 =~ 3 (if you admit a error of 5.263158%)

3 0

3 years ago

Read 2 more answers

A transformation translates the point S (-1,1) down 2 units and right 3 units. What rule describes this translation. A. (x,y)=(x

allochka39001 [22]

The answer is D (x+3,y-2)

4 0

3 years ago

Two opposite sides of a parallelogram are 3x-8 and 10x+13. Find the measure of all sides

RSB [31]

Answer:

Step-by-step explanation:

Using the parallelogram theorem

3x-8 = 10x+13

-7x = 21

x = -3

Substitute

3(-3) - 8

-17

10(-3) + 13

-17

5 0

3 years ago

An adult ticket to a museum costs 3$ more than a children’s ticket. When 200 adult tickets and 100 children tickets are sold, th

antiseptic1488 [7]

The cost of children’s ticket is $ 5

<h3><u>Solution:</u></h3>

Let "c" be the cost of one children ticket

Let "a" be the cost of one adult ticket

Given that adult ticket to a museum costs 3$ more than a children’s ticket

<em>Cost of one adult ticket = 3 + cost of one children ticket</em>

a = 3 + c ------ eqn 1

<em><u>Given that 200 adult tickets and 100 children tickets are sold, the total revenue is $2100</u></em>

200 adult tickets x cost of one adult ticket + 100 children tickets x cost of one children ticket = 2100

$200 \times a + 100 \times c = 2100$

200a + 100c = 2100 ------ eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>

Substitute eqn 1 in eqn 2

200(3 + c) + 100c = 2100

600 + 200c + 100c = 2100

600 + 300c = 2100

300c = 1500

Thus the cost of children’s ticket is $ 5

6 0

3 years ago