Side MN = 6, side OM = 9, side PQ = 6, and side RP = 9. What side corresponds to side NO and can be used to show that ΔMNO ≅ ΔPQ
2 answers:
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Answer:
Step-by-step explanation:
V = 1/3 pi r^2 h Multiply both sides by 3
3V = pi r^2 h Divide by pi * h
= r^2 Take the square root
= r
