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3 years ago

On the previous problem, you found a unit rate of ounces per box. Explain how you find a unit rate when given a rate.

Mathematics

2 answers:

makkiz [27]3 years ago

7 0

Answer:

Sample Response: First, I would write the rate as a fraction. Then I would divide the numerator by the denominator.

give the person above me brainliest ↑↑↑

hope it helps :b

Dima020 [189]3 years ago

4 0

Divide the numerator and the denominator of the given rate by the denominator of the given rate. so in this case, divide the numerator and denominator of 70/5 by 5 to get 14/1 or 14 students per class

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G(x)=9x-11 find g(8)

sineoko [7]

Answer:

Step-by-step explanation:

8(9x-11)

72x-88

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3 years ago

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marusya05 [52]

Answer:

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2 years ago

Read 2 more answers

Which of the following is a polynomial with roots: − square root of 5 , square root of 5 , and −3?

tresset_1 [31]

Roots: - √5 , √5, and - 3

=> these are factors of the polynomial: (x + √5), (x - √5), and (x + 3).

Multiply those three factors:

(x + √5) (x - √5) ( x + 3) = [x^2 - 5] ( x + 3 ) = x^2 + 3x^2 - 5x - 15

Therefore the polynomial x^2 + 3x^2 - 5x - 15 is a polynomial with the given roots.

Answer: option B. x^3 + 3x^2 - 5x - 15

4 0

3 years ago

How much fencing will John need? Use 22/7 for x.

Serjik [45]

Well 22/7 is 3.14 and so on but since there is a little more than 3 you need to make sure he covers up all the fencing places... SO John will need 4 fences

4 0

3 years ago

The sum of the diagonals of a rhombus is 5√2.

Alex

Greetings!
Let ABCD be a rhombus
AC + BD = 5√2 cm

Area of ABCD = Ar△ABD + Ar △BCD
$= \frac{1}{2} \times BD \times AO + \frac{1}{2} \times BD \times OC$
$= \frac{1}{2} BD (AO + OC)$
$\frac{1}{2} BD \times AC$

$So, \frac{ BD \times AC}{2} = 4 \: cm {}^{2}$
$BD \times AC = 8$
$Now, AC + \: BD = 5 \sqrt{2}$

Squaring both sides, we get
$AC {}^{2} + BD {}^{2} + 2 AC.BD =50$
$AC {}^{2} + BD {}^{2} + 2 \times 8 = 50$
$AC {}^{2} + BD {}^{2} = 50 - 16$
$AC {}^{2} + BD {}^{2} = 34$

In △AOB, we have
$OA {}^{2} + OB {}^{2} =AB {}^{2}$
$( \frac{ AC }{2} ) {}^{2} + ( \frac{ BD}{2} ) {}^{2} = AB {}^{2}$
$\frac{ AC {}^{2} } {4} + \frac{ BD {}^{2} }{4} = AB {}^{2}$
$AC {}^{2} + BD {}^{2} = 4 AB {}^{2}$
$34 = 4 AB {}^{2}$

Square rooting both sides
$\sqrt{34} = 2 AB$
$Perimeter = 4 \: AB \\ = 2 \times 2 \: AB \\ = 2 \: \times \sqrt{34 } \\ = 2 \sqrt{34 \: } units$ .

Hope it helps!

7 0

3 years ago