Answer:
9.434 units
Step-by-step explanation:
Given data
points (5,4) and (-3,-1)
x1= 5
y1= 4
x2= -3
y2= -1
The expression for the distance between two points is
d=√((x_2-x_1)²+(y_2-y_1)²)
substitute
d=√((-3-5)²+(-1-4)²)
d=√((-8)²+(-5)²)
d=√64+25
d=√89
d=9.4339
d= 9.434 units
Hence the distance between the points is 9.434 units
P = 2(L + W)
P = 150
L = 5W + 7
150 = 2(5W + 7 + W)
150 = 2(6W + 7)
150 = 12W + 14
150 - 14 = 12W
136 = 12W
136/12 = W
11.33 (or 11 1/3) = W <=== width
L = 5W + 7
L = 5(34/3) + 7
L = 170/3 + 7
L = 170/3 + 21/3
L = 191/3 (or 63 2/3) = L <=== length
Answer:
25
Step-by-step explanation:
Answer:
Step-by-step explanation:
8.3456
9.7103
10.4356
74.8021
430.967
