Answer:
C ) y + 3 = 1/4 ( x + 4 )
Explanation:
Given that you did not include the "given line", I can help you by explaning how to solve this kind of problems, step by step.
The procedure is based of the property of perpendicular lines: the product of the slopes of perpedicular lines is negative 1.
If you call m1, the slope of a line and m2 the slope of a perpendicular line, then:
m1 * m2 = - 1, and you can solve for either m1 or m2:
m1 = - (1 / m2)
m2 = - (1 / m1).
With that this is the procedure:
1) find the slope of the "given line". Name it m1.
2) find the slope of the perpendicular line:
m2 = - (1 / m1).
3) Use the equation of the line with the point (x1,y1) and slope m2
y - y1
-------- = m2
x - x1
4) In this case the point is (-4, - 3)=> x1 = - 4, y1 = - 3
=>
y - (-3)
---------= m2
x - (-4)
=> y + 3 = m2 * (x + 4)
=> y = m2*x + m2 * 4 - 3
Which is the point-slope form. You only have to replace m2 with the slope value of the perpendicular line, which I already explained that you find as m2 = (-1/m1).
Taking that the other line has m1 = - 4 so m2 = 1/4
y = (1/4)x + (1/4) * 4 - 3
y = (1/4) (x +4) - 3
y + 3 = (1/4) (x + 4) and answer is:
C ) y + 3 = 1/4 ( x + 4 )
A
2/9=9/2
-9/2=-2/9
9/2=2/9
-2/9=-9/2
Answer:
ab<6 units
Step-by-step explanation:
One of the basic property of any triangle is that the sum of the length of any two sides of a triangle is always greater than the length of the third side.
Here we are given a triangle abc, in whicn bc=4
ac= 8-ab
If have to make some conclusion about ab.
As per the property discussed above
ab<ac+bc
ab<8-ab+4
2ab<12
ab<6
Hence the length of ab must be less than 6 units
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