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3 years ago

CAN SOMEONE TRANSLATE THESE INTO EQUATIONS PLSS!!!

Mathematics

1 answer:

OleMash [197]3 years ago

7 0

Answer:

Here's 1-3

Step-by-step explanation:

x + 5 =20

2 x $\frac{x}{3}\\$ = 17

$\frac{2}{3}$ + x = 11

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How do you do fractions in simplest form?

disa [49]

To simplify a fraction, you need to find a common factor between the numerator and the denomenator, and divid both parts by that until you cannot anymore.

exg 84/54

both 84 and 54 are divisible by 2 ->
84 divided by 2 = 42
54 divided by 2 = 27

now, both 42 and 27 are divisible by 3 ->
42 diveded by 3 = 14
27 divisible by 3 = 9

so we are currently at 14/9. they have no common factor, so we cannot divide them further.

to completely simplify this, we will turn 14/9 into 1 and 5/9 (this is because 9 fits into 14 once, and the remainder is 5).

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3 years ago

Helpppp!!!!! What is the reason for line 2?

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4 years ago

Hey! Can someone check my answers?

Andrew [12]

The greatest common factor is the biggest number taken from the values.

Q1. The answer is A. 5y^6

$20 y^{9} +5 y^{6}= 4*5 y^{9}+5 y^{6}$
Since $x^{a}* x^{b} =x^{a+b}$ , then $x^{9}= x^{3}* x^{6}$

Back to our expression:
$4*5 y^{9}+5 y^{6}=4*5 y^{3}*y^{6}+5 y^{6}=4 y^{3}*5y ^{6}+ 5y ^{6}*1=5 y^{6} (4y ^{3} +1)$
The greatest common factor is thus $5 y^{6}$

Q2. The answer is D. 12xy^2

$12x y^{5}+60 x^{4} y^{2} -24 x^{3} y^{3}=12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}$
We will use the rule $x^{a}* x^{b} =x^{a+b}$ to factorise the exponents:
$12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}= \\ =12x*y^{2}*y^{3}+5*12*x* x^{3} *y^{2}-2*12x* x^{2} *y*y^{2}= \\ =12xy^{2}*y^{3}+12xy^{2}*5 x^{3} -12xy^{2}*2 x^{2} y= \\ =12xy^{2}(y^{3}+5 x^{3}-2 x^{2} y)$
The greatest common factor is thus $12xy^{2}$

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4 years ago

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