Question

A movie theater has a seating capacity of 329. The theater charges $5.00 for children, $7.00 for students, and $12.00 of adults. There are half as many adults as there are children. If the total ticket sales was $ 2388, How many children, students, and adults attended?
___ children attended.
___students attended.
____adults attended.

Answer 1

Answer:

170 children

74 students

85 adults

Step-by-step explanation:

Given

Let:

$C = Children; S = Students; A = Adults$

For the capacity, we have:

$C + S + A = 329$

For the tickets sold, we have:

$5C + 7S + 12A = 2388$

Half as many as adults are children implies that:

$A = \frac{C}{2}$

Required

Solve for A, C and S

The equations to solve are:

$C + S + A = 329$ -- (1)

$5C + 7S + 12A = 2388$ -- (2)

$A = \frac{C}{2}$ -- (3)

Make C the subject in (3)

$C = 2A$

Substitute $C = 2A$ in (1) and (2)

$C + S + A = 329$ -- (1)

$2A + S + A = 329$

$3A + S = 329$

Make S the subject

$S = 329 - 3A$

$5C + 7S + 12A = 2388$ -- (2)

$5*2A + 7S + 12A = 2388$

$10A + 7S + 12A = 2388$

$7S + 22A = 2388$

Substitute $S = 329 - 3A$

$7(329 - 3A) + 22A = 2388$

$2303 - 21A + 22A = 2388$

$2303 +A = 2388$

Solve for A

$A = 2388 - 2303$

$A = 85$

Recall that: $C = 2A$

$C = 2 * 85$

$C = 170$

Recall that: $S = 329 - 3A$

$S = 329 - 3 * 85$

$S = 329 - 255$

$S = 74$

Hence, the result is:

$C = 170$

$S = 74$

$A = 85$