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Alina [70]
3 years ago
10

a handful of coins has the value of 1 dollar and 79 cents there are 3 times as many dimes as quarters and 5 more pennies than di

mes if there are only 3 types of coins how many of each type of coin are there
Mathematics
1 answer:
eduard3 years ago
5 0

Answer:

3 Quarters 9 dimes 14 pennies

Step-by-step explanation:

so dimes are x, quarters are y, and pennies are z. Next we know that x*3 y is what dimes are and 5 more pennies then dimes so z+5. Now we do 3 quarters since thats about 100  but less then 3*3=9 so 190 we have 90+75 cents now then we add 14 the cursed number lol but we add 14 because 9+5 is 14 and there are 5 more pennies then dimes.

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Answer: the second column is 12,  then 15, then 6

Step-by-step explanation:

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6 0
3 years ago
The height of a model rocket is 4.5% of the height of the actual rocket.The model is 1.22 m high.How high is the actual rocket
Serjik [45]

Answer:

Actual Height = 27.11 m

Step-by-step explanation:

Given:

Height of model rocket = 4.5 % of actual Height

Model Height = 1.22 m

To Find:

Actual Height of rocket = ?

Solution:

We have to Find the Actual Height of the rocket

Let actual height be x

Now it is given that

Height of model rocket = 4.5 % of actual Height

As we have the values so putting it in it becomes

1.22 = 4.5 % * x

it could be written as

1.22=\frac{4.5}{100}*x

Multiplying both sides by \frac{100}{4.5}

it becomes

1.22*\frac{100}{4.5} = x

\frac{122}{4.5} = x

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or

Actual Height = 27.11 m

6 0
3 years ago
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Inessa05 [86]

Answer:

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5 0
3 years ago
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State the excluded values for each. 60x^3/12x
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3 years ago
A quality control inspector samples 2 computer chips from a box containing 13 computer chips. If the box contains 3 defective ch
elena-14-01-66 [18.8K]

Answer:

The number of ways to select a sample of 2 computer chips so that at least one of the chips is defective is 33 ways.

Step-by-step explanation:

The box contains 13 computer chips. Of these 13 chips 3 are defective and 10 are good.

A quality control inspector samples 2 computer chips.

The number of ways to select at least 1 defective chip is:

n (At least 1 defective chip) = n (1 defective chip) + n (2 defective chips)

The number of ways to select 1 defective chip is: {3\choose 1}{10\choose 1}=3\times10=30 ways.

The number of ways to select 2 defective chips is:{3\choose 2}{10\choose 0}=3\times1=3 ways.

n (At least 1 defective chip) = n (1 defective chip) + n (2 defective chips)

                                             = 30 + 3

                                             = 33

Thus, the number of ways to select a sample of 2 computer chips so that at least one of the chips is defective is 33 ways.

5 0
3 years ago
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