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asambeis [7]
3 years ago
13

Very Important) I need help with all my Math questions if your excellent at math and is passing your math class can you click on

my name and go to my math questions and please help me with them. If correct and you need to show your work ill mark you Brainliest. Also I need Help with Health Questions also. Some have 1 answer but they aren't correct still need help with them. ​
Mathematics
1 answer:
Lady_Fox [76]3 years ago
6 0

Answer:

Where are the questions

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Help is all I need..
Solnce55 [7]

Answer:

{(x - 1)}^{2}   = 16 \\ x - 1  =  |4| \\ x  =  |4|   + 1

x = +4 +1

x = +5

and

x = -4 + 1

x = -3

7 0
3 years ago
Read 2 more answers
Select all the ways you can Solve rates and ratios?​
worty [1.4K]

Answer:

find the constant rate of proportionality

Step-by-step explanation:

7 0
3 years ago
3. Mrs. Smith's class took a survey and found that 9 of 13 students prefer two scoops of ice cream versus one scoop of ice cream
Murljashka [212]
9/13=x/104
9•104=13x
936=13x
X=72
3 0
2 years ago
What is 24^2? Use mental math.
AnnZ [28]

Answer:

576

Step-by-step explanation:

calculator

5 0
3 years ago
PLEASE HELP!!!!!!!!!!!!! DUE SOON
Sergio039 [100]

\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ h=-16t^2+\stackrel{\stackrel{v_o}{\downarrow }}{65}t


now, take a look at the picture below, so for 2) and 3) is the vertex of this quadratic equation, 2) is the y-coordinate and 3) the x-coordinate.


\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ h=\stackrel{\stackrel{a}{\downarrow }}{-16}t^2\stackrel{\stackrel{b}{\downarrow }}{+65}t\stackrel{\stackrel{c}{\downarrow }}{+0} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left( -\cfrac{65}{2(-16)}~~,~~0-\cfrac{65^2}{4(-16)} \right) \implies \left( \cfrac{65}{32}~,~0- \cfrac{4225}{-64}\right)


\bf \left( \cfrac{65}{32}~,~0+ \cfrac{4225}{64}\right)\implies \left( \stackrel{seconds}{2\frac{1}{32}}~~,~~ \stackrel{feet~hight}{66\frac{1}{64}}\right)

6 0
3 years ago
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