Consider the function
First, factor it:
![G(x) = -2x^3 - 15x^2 + 36x=-x(2x^2+15x-36)=\\ \\=-x\cdot 2\cdot \left(x-\dfrac{-15-\sqrt{513}}{4}\right)\cdot \left(x-\dfrac{-15+\sqrt{513}}{4}\right).](https://tex.z-dn.net/?f=G%28x%29%20%3D%20-2x%5E3%20-%2015x%5E2%20%2B%2036x%3D-x%282x%5E2%2B15x-36%29%3D%5C%5C%20%5C%5C%3D-x%5Ccdot%202%5Ccdot%20%5Cleft%28x-%5Cdfrac%7B-15-%5Csqrt%7B513%7D%7D%7B4%7D%5Cright%29%5Ccdot%20%5Cleft%28x-%5Cdfrac%7B-15%2B%5Csqrt%7B513%7D%7D%7B4%7D%5Cright%29.)
The x-intercepts are at points ![\left(\dfrac{-15-\sqrt{513} }{4},0\right),\ (0,0),\ \left(\dfrac{-15+\sqrt{513} }{4},0\right).](https://tex.z-dn.net/?f=%5Cleft%28%5Cdfrac%7B-15-%5Csqrt%7B513%7D%20%7D%7B4%7D%2C0%5Cright%29%2C%5C%20%280%2C0%29%2C%5C%20%5Cleft%28%5Cdfrac%7B-15%2B%5Csqrt%7B513%7D%20%7D%7B4%7D%2C0%5Cright%29.)
1. From the attached graph you can see that
- function is positive for
![x\in \left(-\infrty, \dfrac{-15-\sqrt{513} }{4}\right)\cup \left(0,\dfrac{-15+\sqrt{513} }{4}\right);](https://tex.z-dn.net/?f=x%5Cin%20%5Cleft%28-%5Cinfrty%2C%20%5Cdfrac%7B-15-%5Csqrt%7B513%7D%20%7D%7B4%7D%5Cright%29%5Ccup%20%5Cleft%280%2C%5Cdfrac%7B-15%2B%5Csqrt%7B513%7D%20%7D%7B4%7D%5Cright%29%3B)
- function is negative for
![x\in \left(\dfrac{-15-\sqrt{513} }{4},0\right)\cup \left(\dfrac{-15+\sqrt{513} }{4},\infty\right).](https://tex.z-dn.net/?f=x%5Cin%20%5Cleft%28%5Cdfrac%7B-15-%5Csqrt%7B513%7D%20%7D%7B4%7D%2C0%5Cright%29%5Ccup%20%5Cleft%28%5Cdfrac%7B-15%2B%5Csqrt%7B513%7D%20%7D%7B4%7D%2C%5Cinfty%5Cright%29.)
2. Since
the function is neither even nor odd.
3. The domain is
the range is
Median - 6.5
mode- 6.5
mean-5.8
In order from least to greatest:
5/10 , 7/12 , 4/6
You have to find a common denominator of all 3 numbers which is 60 and then you proceed with the next steps.
Answer:
(This is for the pizza question)The area of the box is 900 cm, so subtract 900 cm from the area of the circle which is (3.14)[times radius which is 12(half of 24) squared] [144*3.14] So the area of the circle is 452.16 which you get from the area formula of pi times radius squared.
Step-by-step explanation:
Find the area of the box first, then subtract it by the area of the circle. (please thank me for it)
Answer:
![x\leq 1.78](https://tex.z-dn.net/?f=x%5Cleq%201.78)
Step-by-step explanation:
We are given that
Width of pool, b=4.5 m
We have to find the inequality which represents the possible lengths of the wading pool.
Let x be the length of wading pool
We know that
Area of rectangle=![length\times breadth](https://tex.z-dn.net/?f=length%5Ctimes%20breadth)
According to question
Using the formula
![4.5x\leq 8](https://tex.z-dn.net/?f=4.5x%5Cleq%208)
Divide by 4.5 on both sides we get
![x\leq\frac{8}{4.5}](https://tex.z-dn.net/?f=x%5Cleq%5Cfrac%7B8%7D%7B4.5%7D)
![x\leq 1.78](https://tex.z-dn.net/?f=x%5Cleq%201.78)