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8_murik_8 [283]
3 years ago
10

HELP DUE AT 8: 30 ASAP!

Mathematics
1 answer:
Gala2k [10]3 years ago
3 0
These r lowkey hard i have no clue tbh sorry
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Charles will babysit for up to 4 hours and charges $7 per hour. Write a function in function notation for this situation.
I am Lyosha [343]
Assume Charles charges $7*3=$21 if he babysits for 2,5 hours (that is 2 and a half hours).

That is we are not considering Charles babysitting exactly 1, 2, 3 or 4 hours, but also in between times.


then we can write the following piecewise function to describe the situation:


f is a function from (0, 4] to {$7, $14, $21, $28}

f(x)=\begin{cases} 
      \$7 & if \enspace \enspace x\leq 1 \\
      \$14 & if \enspace \enspace 1\ \textless \  x\leq 2 \\
      \$21 & if \enspace\enspace 2\ \textless \ x\leq 3 \\
      \$28 & if \enspace\enspace 3\ \textless \ x\leq 4 \
   \end{cases}
6 0
3 years ago
Find the measurement of Angle SPQ
Harrizon [31]

Answer:

146 °

Step-by-step explanation:

sum of angles in circle = 360°

360 - 154-60-86 = 60

60 = UPS

SPQ = UPS + QUP = 60 + 86 = 146°

6 0
3 years ago
Read 2 more answers
Graph f(x) = 3x + 2 <br> PLEASE HURRY
PtichkaEL [24]

Answer:

See attached

Step-by-step explanation:

<u>Given</u>

  • f(x) = 3x + 2

The graph for the function is attached

5 0
3 years ago
A 25% acid solution must be added to a 40% solution to get 240 liters of 30% acid solution. How many of each should be used ?
schepotkina [342]

Answer:

The number of liters of 25% acid solution = x = 160 liters

The number of liters of 40% acid solution = y = 80 liters

Step-by-step explanation:

Let us represent:

The number of liters of 25% acid solution = x

The number of liters of 40% acid solution = y

Our system of Equations =

x + y = 240 liters....... Equation 1

x = 240 - y

A 25% acid solution must be added to a 40% solution to get 240 liters of 30% acid solution.

25% × x + 40% × y = 240 liters × 30%

0.25x+ 0.4y = 72...... Equation 2

We substitute 240 - y for x in Equation 2

0.25(240 - y)+ 0.4y = 72

60 - 0.25y + 0.4y = 72

Collect like terms

- 0.25y + 0.4y = 72 - 60

0.15y = 12

y = 12/0.15

y = 80 Liters

Solving for x

x = 240 - y

x = 240 liters - 80 Liters

x = 160 liters

Therefore,

The number of liters of 25% acid solution = x = 160 liters

The number of liters of 40% acid solution = y = 80 liters

5 0
3 years ago
What is 3/2=9/10k im having troble lots rly
tigry1 [53]

Answer:

k=  5 over 3  =1.667

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    (3)/(2)-((9)/(10)*k)=0

simplify 9/10

 3      9

 — -  (—— • k)  = 0  

 2     10

simplify 3/2

 3    9k

 — -  ——  = 0  

 2    10

   Find the Least Common Multiple

     The left denominator is :       2  

     The right denominator is :       10

Least Common Multiple:

     10

Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M  

   Denote the Left Multiplier by  Left_M  

   Denote the Right Multiplier by  Right_M  

   Denote the Left Deniminator by  L_Deno  

   Denote the Right Multiplier by  R_Deno  

  Left_M = L.C.M / L_Deno = 5

  Right_M = L.C.M / R_Deno = 1

Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      3 • 5

  ——————————————————  =   —————

        L.C.M              10  

  R. Mult. • R. Num.      9k

  ——————————————————  =   ——

        L.C.M             10

Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

3 • 5 - (9k)     15 - 9k

————————————  =  ———————

     10            10  

Pull out like factors :

  15 - 9k  =   -3 • (3k - 5)

-3 • (3k - 5)

 —————————————  = 0  

      10      

When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 -3•(3k-5)

 ————————— • 10 = 0 • 10

    10    

Now, on the left hand side, the  10  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  -3  •  (3k-5)  = 0

Solve :    -3   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solve  :    3k-5 = 0  

Add  5  to both sides of the equation :  

                     3k = 5

Divide both sides of the equation by 3:

                    k = 5/3 = 1.667

one solution was found

k = 5/3 = 1.667

hope it helps sry its so long

7 0
4 years ago
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